Please help for a forloop scan

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01/29/2021 at 12:20 AM #159748 quote

Ha
Participant

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Hi,

I’m trying to scan that N number of consecutive candles are bullish and above 20EMA.

I used a forloop to scan and I’m not getting a correct result.

Can someone please tell me if you see a problem with my code? or is there other way to code it?

Thank you.

Long_20EMA.itf

01/29/2021 at 1:23 AM #159751 quote
robertogozzi
Moderator

Legend
I can’t read your code now (you’d better always post also the code, unless it’s over hundreds of lines).

This is the code:
```
N       = 5   //5 consecutive candles
Ema20   = close > average[20,0](close)
Bullish = close > open
Cond    = Ema20 AND Bullish
x       = (summation[N](Cond) = N)
```
x is true whenever N consecutive bullish candles above ema20 are met.
01/29/2021 at 9:03 AM #159764 quote
Ha
Participant

New
Hi

Thank you for the help.

I’d already tried the summation fonction before, it doesn’t work well.

That’s why I tried a forloop.

Here’s my entire code.
```
// N number of candles close above 20EMA and are bullish green


// Uptrend
ema20 = ExponentialAverage[20](close)
ema50 = ExponentialAverage[50](close)
ema200 = ExponentialAverage[200](close)
m1 = ema20 > ema50 and ema50 > ema200
m2 = ema20 > ema20[1]

// Bullish candles above 20EMA
NofBar = 5
rsltClose = 0
rsltCandle = 0
for i = 0 to NofBar do

rsltClose = close[i] >  ema20
rsltCandle = close[i] > open[i]

next

// Volume & Price
vol = ExponentialAverage[60](Volume)
t1 = vol > 500000
t2 = close > 3 and close < 40


SCREENER[m1 and m2 and rsltClose and rsltCandle and t1 and t2]
```
01/29/2021 at 10:52 AM #159780 quote
robertogozzi
Moderator

Legend
My fault, I coded an SMA instead of EMA. Replace line 2 with:
```
Ema20   = close > average[20,1](close)  //0=Sma, 1=Ema, 2=Wma, etc...
```
Ha thanked this post
01/29/2021 at 1:04 PM #159827 quote

Ha
Participant

New

Hi Roberto

Your code works, thank you.

Would you mind explain how the last line works ?

Can’t get my head around how you can give a condition in a price constant () then an arithmetic sum of that condition can bring back what I want.

01/29/2021 at 2:16 PM #159837 quote

robertogozzi
Moderator

Legend

It sums up the condition for the last N bars and the result must be N, otherwise it would mean that the condition is not true for all N bars.
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