Please help for a forloop scan

• 01/29/2021 at 12:20 AM #159748
  Ha

  Hi,

  I’m trying to scan that N number of consecutive candles are bullish and above 20EMA.

  I used a forloop to scan and I’m not getting a correct result.

  Can someone please tell me if you see a problem with my code? or is there other way to code it?

  Thank you.

  

  Ha

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  01/29/2021 at 1:23 AM #159751
  robertogozzi

  I can’t read your code now (you’d better always post also the code, unless it’s over hundreds of lines).

  This is the code:

  N = 5 //5 consecutive candles Ema20 = close > average[20,0](close) Bullish = close > open Cond = Ema20 AND Bullish x = (summation[N](Cond) = N)

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  N       = 5   //5 consecutive candles Ema20   = close > average[20,0](close) Bullish = close > open Cond    = Ema20 AND Bullish x       = (summation[N](Cond) = N)

  x is true whenever N consecutive bullish candles above ema20 are met.

   

  

  robertogozzi

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  01/29/2021 at 9:03 AM #159764
  Ha

  Hi

  Thank you for the help.

  I’d already tried the summation fonction before, it doesn’t work well.

  That’s why I tried a forloop.

  Here’s my entire code.

  // N number of candles close above 20EMA and are bullish green // Uptrend ema20 = ExponentialAverage[20](close) ema50 = ExponentialAverage[50](close) ema200 = ExponentialAverage[200](close) m1 = ema20 > ema50 and ema50 > ema200 m2 = ema20 > ema20[1] // Bullish candles above 20EMA NofBar = 5 rsltClose = 0 rsltCandle = 0 for i = 0 to NofBar do rsltClose = close[i] > ema20 rsltCandle = close[i] > open[i] next // Volume & Price vol = ExponentialAverage[60](Volume) t1 = vol > 500000 t2 = close > 3 and close < 40 SCREENER[m1 and m2 and rsltClose and rsltCandle and t1 and t2]

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  // N number of candles close above 20EMA and are bullish green     // Uptrend ema20 = ExponentialAverage[20](close) ema50 = ExponentialAverage[50](close) ema200 = ExponentialAverage[200](close) m1 = ema20 > ema50 and ema50 > ema200 m2 = ema20 > ema20[1]   // Bullish candles above 20EMA NofBar = 5 rsltClose = 0 rsltCandle = 0 for i = 0 to NofBar do   rsltClose = close[i] >  ema20 rsltCandle = close[i] > open[i]   next   // Volume & Price vol = ExponentialAverage[60](Volume) t1 = vol > 500000 t2 = close > 3 and close < 40     SCREENER[m1 and m2 and rsltClose and rsltCandle and t1 and t2]

   

  

  Ha

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  01/29/2021 at 10:52 AM #159780
  robertogozzi

  My fault, I coded an SMA instead of EMA. Replace line 2 with:

  Ema20 = close > average[20,1](close) //0=Sma, 1=Ema, 2=Wma, etc...

  1	Ema20   = close > average[20,1](close)  //0=Sma, 1=Ema, 2=Wma, etc...

   

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  Ha

  

  robertogozzi

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  01/29/2021 at 1:04 PM #159827
  Ha

  Hi Roberto

  Your code works, thank you.

  Would  you mind explain how the last line works ?

  Can’t get my head around how you can give a condition in a price constant () then an arithmetic sum of that condition can bring back what I want.

  

  Ha

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  01/29/2021 at 2:16 PM #159837
  robertogozzi

  It sums up the condition for the last N bars and the result must be N, otherwise it would mean that the condition is not true for all N bars.

   

  

  robertogozzi

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