Counting green candles

• 02/20/2023 at 8:03 PM #209997
  JenniferStrateg

  I am trying to code a backtest of a strategy, where I need to count the green candles to get my exit signal. Exit is on close of the first red candle after 3 green candles. Any ideas as to how I code that? I only have part of an idea – something with fractions and true or false. But even if that works – which it doesn’t right now – I still haven’t solved the exit on the red candle. Hope to hear your ideas. Half solutions or quater solutions are more than welcome!

  Thank you and hope you write some great stuff today 🙂

  

  JenniferStrateg

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  02/20/2023 at 8:18 PM #209998
  JC_Bywan

  Sthg like that…

  myred = Close<Open my3green = summation[3](Close>Open)=3 mysequence = my3green[1] and myred if longonmarket and mysequence then sell at market endif

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  myred = Close<Open my3green = summation[3](Close>Open)=3 mysequence = my3green[1] and myred   if longonmarket and mysequence then   sell at market endif

   

   

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  Midlanddave

  

  JC_Bywan

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  02/20/2023 at 9:49 PM #210005
  JenniferStrateg

  Hi JC

  Thank you! That is so cool. Had no clue the summation could be used like that. And of course the red is as simple as that.

  Thank you!!

  

  JenniferStrateg

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  02/23/2023 at 10:01 PM #210341
  JenniferStrateg

  Hi again

  I’ve tested it on several instruments and I think it comes back with an exit after 3 green bars and one red in a row. Do you have any ideas for 3 green bars mixed with red bars (and then one red after that). There can be red bars mixed in between the 3 green ones.

  All the best.

  

  JenniferStrateg

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  02/24/2023 at 8:15 AM #210351
  JC_Bywan

  How many reds allowed between 1st and 2nd green, and between 2nd and 3rd green?

  

  JC_Bywan

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  02/24/2023 at 9:36 AM #210355
  JenniferStrateg

  As many as it takes. Let’s say 15.

  

  JenniferStrateg

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  02/24/2023 at 8:47 PM #210449
  JC_Bywan

  Ok, I’ve made the 15 a parameter Nredmax you can change if you want to. You just have to define your entry conditions before trying it. To be tested.

  Nredmax=15 Nsequencemax=Nredmax+4// 3 greens + red at the end + Nredmax in between the 3 greens green= close>open red= close<open if not longonmarket  and  yourentryconditions  then // define your entry conditions buy 1 contract at market endif if longonmarket and not longonmarket[1] then barstart=barindex endif if summation[2](longonmarket)=2 and green[1] and red then bartotal=barindex-barstart+1 vendre = (bartotal<=Nsequencemax and summation[bartotal](green)>=3) or (bartotal>Nsequencemax and summation[Nsequencemax](green)>=3) if vendre then sell at market endif endif

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  Nredmax=15   Nsequencemax=Nredmax+4// 3 greens + red at the end + Nredmax in between the 3 greens green= close>open red= close<open   if not longonmarket  and  yourentryconditions  then // define your entry conditions   buy 1 contract at market endif   if longonmarket and not longonmarket[1] then   barstart=barindex endif if summation[2](longonmarket)=2 and green[1] and red then   bartotal=barindex-barstart+1   vendre = (bartotal<=Nsequencemax and summation[bartotal](green)>=3) or (bartotal>Nsequencemax and summation[Nsequencemax](green)>=3)   if vendre then     sell at market   endif endif

   

   

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  Midlanddave

  

  JC_Bywan

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  02/25/2023 at 10:44 AM #210463
  JenniferStrateg

  Thanks for taking the time to do this!

  

  JenniferStrateg

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