Equal to highest percentage change in 2 days

mykologen · 2017-07-22T09:12:49+00:00

Hello Issue with percentage change. The idea is following: “The precentage change today should be equal to the highest percenage change in 2 days. Measured close to close.” I am trying to use the simplified creation as far as I can and then supplement the strategy manually in the end. With Variation I have added following (c7): // Conditions to enter short positions c4 = (close[1] > close[2]) c5 = (close > close[1]) indicator4 = Average[200](close) c6 = (close < indicator4) indicator5 = Variation(close) c7 = (indicator5 = indicator5[2]) So question is how do I rewrite the code so its equal to the highest percenage change in 2 days (close to close)? As it is right now, checks only 2 days ago. Maybe its even possible to do it with simplified creation?

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07/22/2017 at 10:12 AM #41359 quote

mykologen
Participant

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Hello

Issue with percentage change. The idea is following:

“The precentage change today should be equal to the highest percenage change in 2 days. Measured close to close.”

I am trying to use the simplified creation as far as I can and then supplement the strategy manually in the end. With Variation I have added following (c7):

// Conditions to enter short positions
c4 = (close[1] > close[2])
c5 = (close > close[1])
indicator4 = Average[200](close)
c6 = (close < indicator4)
indicator5 = Variation(close)
c7 = (indicator5 = indicator5[2])

So question is how do I rewrite the code so its equal to the highest percenage change in 2 days (close to close)?
As it is right now, checks only 2 days ago. Maybe its even possible to do it with simplified creation?

07/29/2017 at 6:58 PM #41968 quote

JC_Bywan
Moderator

Master

if your 2 days variations are “yesterday to today” and “day before yesterday to yesterday” then you’d want:
c7 = indicator5>=indicator5[1]

08/02/2017 at 5:19 PM #42347 quote

mykologen
Participant

Average

Thanks for your answer.

Would I be able to write the code like this:

c9 = variation(close) >= (variation(close[1]) and variation(close[2]))

So, variation today is equal or higher than (the variation yesterday and the day before yesterday)?

08/03/2017 at 10:55 AM #42393 quote
Nicolas
Keymaster

Legend
No, you need to type 2 times the condition:
```
c9 = (variation(close) >= variation(close[1])) AND (variation(close) >= variation(close[2]))
```
mykologen thanked this post
08/03/2017 at 3:28 PM #42416 quote

mykologen
Participant

Average

Thanks and appologies for my “beginner” questions… 🙂
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Equal to highest percentage change in 2 days

ProOrder: Automated Strategies & Backtesting

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This topic contains 4 replies,
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9 years, 1 month ago.

Topic Details

Forum:	ProOrder: Automated Strategies & Backtesting
Language:	English
Started:	07/22/2017
Status:	Active
Attachments:	No files