Detect cross 4 hour pivots? (incl. example)

• 12/13/2023 at 7:17 AM #225165
  Robin81

  I am working on creating a strategy in which a candle passes through the lines of a 4-hour pivot. The formulas of the pivots correspond to IG Markets, so the values of the pivots correspond to the standard indicator in pro real time.
  The script below does not work during testing. It gives random results, but not when the lines go through a pivot. What am I overlooking here? In the attachment there is another image to explain the situation.

  Timeframe(4 hours) // Formula Pivots H4 P4 = (high + low + close)/3 P4R1 = (2*P4) - low P4R2 = P4 + high - low P4R3 = high + 2*(P4-low) P4R4 = P4R3 + (high - low) P4S1 = (2*P4) - high P4S2 = P4 - (high - low) P4S3 = low - 2*(high - P4) P4S4 = P4S3 - (high - low) Timeframe(default) Timeframe (1 minute) c1= high[1] > P4 AND low[1] < P4 c2= (high[1] > P4R1 AND low[1] < P4R1) OR (high[1] > P4R2 AND low[1] < P4R2) OR (high[1] > P4R3 AND low[1] < P4R3) OR (high[1] > P4R4 AND low[1] < P4R4) c3= (high[1] > P4S1 AND low[1] < P4S1) OR (high[1] > P4S2 AND low[1] < P4S2) OR (high[1] > P4S3 AND low[1] < P4S3) OR (high[1] > P4S4 AND low[1] < P4S4) IF c1 OR c2 OR c3 THEN signal = 1 screener [ signal > 0 ] sort by signal as "TEST" ENDIF

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

  Timeframe(4 hours) // Formula Pivots H4 P4 = (high + low + close)/3 P4R1 = (2*P4) - low P4R2 = P4 + high - low P4R3 = high + 2*(P4-low) P4R4 = P4R3 + (high - low)   P4S1 = (2*P4) - high P4S2 = P4 - (high - low) P4S3 = low - 2*(high - P4) P4S4 = P4S3 - (high - low)   Timeframe(default)   Timeframe (1 minute) c1= high[1] > P4 AND low[1] < P4 c2= (high[1] > P4R1 AND low[1] < P4R1) OR (high[1] > P4R2 AND low[1] < P4R2) OR (high[1] > P4R3 AND low[1] < P4R3) OR (high[1] > P4R4 AND low[1] < P4R4) c3= (high[1] > P4S1 AND low[1] < P4S1) OR (high[1] > P4S2 AND low[1] < P4S2) OR (high[1] > P4S3 AND low[1] < P4S3) OR (high[1] > P4S4 AND low[1] < P4S4)   IF c1 OR c2 OR c3 THEN signal = 1 screener [ signal > 0 ] sort by signal as "TEST" ENDIF

   

  

  Robin81

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  12/13/2023 at 8:50 AM #225167
  JS

  Hi @Robin81

  Remove “TimeFrame(Default)” in line 14

  A “screener” instruction in an “If… Then” isn’t going to work:

  If C1 or C2 or C3 then

  Signal=1

  EndIf

  Screener[Signal=1]

  

  JS

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  12/13/2023 at 10:14 AM #225186
  Robin81

  @JS,

  I adjusted it, but to no avail. It still gives random notifications.
  It seems like he doesn’t want to take over the value of the pivot?

  

  Robin81

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  12/13/2023 at 10:57 AM #225194
  JS

  Try using High and Low instead of High[1] and Low[1]

  

  JS

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  12/13/2023 at 11:33 AM #225199
  Robin81

  @JS,

  Just did it, but unfortunately without success. I chose [1] so that it looks at the recently closed candle. Unfortunately that’s not the problem. In any case, thanks for your thoughts.

  

  Robin81

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  12/13/2023 at 11:42 AM #225201
  Robin81

  If I place the pivots as a ‘separate indicator’ under the graph, you see that the values of the outcome are equal to the standard pivot in PRT. So the formulas for all pivot values 4 hours are correct. Only detecting when a candle is closed on the line has not been possible so far 🙁

  

  Robin81

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  12/13/2023 at 12:53 PM #225210
  JS

  Hi,

  Try using:
  c1= high > P4[1] AND low < P4[1] (change also for c2 and c3)

  

  JS

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  12/13/2023 at 1:48 PM #225226
  Robin81

  @JS,

  Do you know the reason why you use P4[1] instead of P4? Your idea was the right way, looks like it works! I am very curious about the explanation…. I will continue testing in the coming days.
  Thanks for your quick response, great!

   

  

  Robin81

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  12/13/2023 at 2:13 PM #225227
  JS

  Hi Robin,

  It’s great that it worked.

  For example, suppose you use a current price (Close) to check whether the price is higher or lower than the same current price (Close), then you understand that this is not going to work.

  The solution is to use the previous price (Close[1]) and check it with the current price…

  Close>Close[1] or in this case High>P4[1]

  

  JS

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  01/21/2024 at 10:15 AM #226653
  qigley

  JS wrote:

  Hi @Robin81

  A “screener” instruction in an “If… Then” isn’t going to work:

  Not correct. You can use a SCREENER command in an IF statement.

  

  qigley

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  01/21/2024 at 10:49 AM #226654
  JS

  That’s right, that was already clear and was not the problem…

  

  JS

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