What's wrong in my code?

• 04/19/2016 at 4:53 PM #5673
  rainerb

  what wrong in the code?

  n = 4 h = highest[n] l = lowest[n] once b = 2 v = h if h = high[n-1] and high[n-1] > high and high[n-1] > low and (b = 1 or b = 2 ) then v = h b = 0 else if l = low[n-1] and low[n-1] < low and low[n-1] < high and ( b = 0 or b = 2 ) then v = l b = 1 else v = v[1] endif endif return v

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  n = 4 h = highest[n] l = lowest[n] once b = 2 v = h if h = high[n-1] and high[n-1] > high and high[n-1] > low and (b = 1 or b = 2 ) then v = h b = 0 else if l = low[n-1] and low[n-1] < low and low[n-1] < high and ( b = 0 or b = 2 ) then v = l b = 1 else v = v[1] endif endif return v

   

  

  rainerb

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  04/19/2016 at 8:52 PM #5683
  Nicolas

  Hello rainerd,

  You cannot use the letter “h” for a variable as it is reserved by the programming language.

  Also, on line 2 and 3, you must define the chosen price to look for the highest and lowest. I modified your code a bit, here it is:

  n = 4 hh = highest[n](high) l = lowest[n](low) once b = 2 v = hh if hh = high[n-1] and high[n-1] > high and high[n-1] > low and (b = 1 or b = 2 ) then v = hh b = 0 else if l = low[n-1] and low[n-1] < low and low[n-1] < high and ( b = 0 or b = 2 ) then v = l b = 1 else v = v[1] endif endif return v

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  n = 4 hh = highest[n](high) l = lowest[n](low) once b = 2 v = hh   if hh = high[n-1] and high[n-1] > high and high[n-1] > low and (b = 1 or b = 2 ) then v = hh b = 0 else if l = low[n-1] and low[n-1] < low and low[n-1] < high and ( b = 0 or b = 2 ) then v = l b = 1 else v = v[1] endif endif   return v

   

  Please find attached what we get for your indicator.

  

  Nicolas

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