Please help for a forloop scan

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  • 01/29/2021 at 12:20 AM #159748 quote
    Ha
    Participant
    New

    Hi,

    I’m trying to scan that N number of consecutive candles are bullish and above 20EMA.

    I used a forloop to scan and I’m not getting a correct result.

    Can someone please tell me if you see a problem with my code? or is there other way to code it?

    Thank you.

    Long_20EMA.itf
    01/29/2021 at 1:23 AM #159751 quote
    robertogozzi
    Moderator
    Master

    I can’t read your code now (you’d better always post also the code, unless it’s over hundreds of lines).

    This is the code:

    N       = 5   //5 consecutive candles
Ema20   = close > average[20,0](close)
Bullish = close > open
Cond    = Ema20 AND Bullish
x       = (summation[N](Cond) = N)

    x is true whenever N consecutive bullish candles above ema20 are met.

    01/29/2021 at 9:03 AM #159764 quote
    Ha
    Participant
    New

    Hi

    Thank you for the help.

    I’d already tried the summation fonction before, it doesn’t work well.

    That’s why I tried a forloop.

    Here’s my entire code.

    // N number of candles close above 20EMA and are bullish green


// Uptrend
ema20 = ExponentialAverage[20](close)
ema50 = ExponentialAverage[50](close)
ema200 = ExponentialAverage[200](close)
m1 = ema20 > ema50 and ema50 > ema200
m2 = ema20 > ema20[1]

// Bullish candles above 20EMA
NofBar = 5
rsltClose = 0
rsltCandle = 0
for i = 0 to NofBar do

rsltClose = close[i] >  ema20
rsltCandle = close[i] > open[i]

next

// Volume & Price
vol = ExponentialAverage[60](Volume)
t1 = vol > 500000
t2 = close > 3 and close < 40


SCREENER[m1 and m2 and rsltClose and rsltCandle and t1 and t2]
    01/29/2021 at 10:52 AM #159780 quote
    robertogozzi
    Moderator
    Master

    My fault, I coded an SMA instead of EMA. Replace line 2 with:

    Ema20   = close > average[20,1](close)  //0=Sma, 1=Ema, 2=Wma, etc...
    Ha thanked this post
    01/29/2021 at 1:04 PM #159827 quote
    Ha
    Participant
    New

    Hi Roberto

    Your code works, thank you.

    Would  you mind explain how the last line works ?

    Can’t get my head around how you can give a condition in a price constant () then an arithmetic sum of that condition can bring back what I want.

    01/29/2021 at 2:16 PM #159837 quote
    robertogozzi
    Moderator
    Master

    It sums up the condition for the last N bars and the result must be N, otherwise it would mean that the condition is not true for all N bars.

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Please help for a forloop scan


ProScreener: Market Scanners & Detection

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Ha @ha Participant
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This topic contains 5 replies,
has 2 voices, and was last updated by robertogozzi
5 years, 1 month ago.

Topic Details
Forum: ProScreener: Market Scanners & Detection
Language: English
Started: 01/29/2021
Status: Active
Attachments: 1 files
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