Defining a time frame

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This topic contains 5 replies, has 2 voices, and was last updated by avatar fxbravo 1 week, 2 days ago.

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  • #86440

    Hello gentlemen,

     

    I want to code this need, but I don’t know how to do it!

    My need: I take a simple RSI(14) but I want to check X time by day if the condition is OK or NotOK

     

    Here a drawto show you:

    9h00: the indicator check if the conditon is OK until 12h00 (it’s ok for this)

    14h00: the indicator check again if the condition is ok until 18h00/ It could be OK or NotOK, whatever it happen (OK or NotOK) between 9h/13h59 (like it’s the begining of the day, minus the timeframe 9h00/13h59)

     

    So, my problem is to “reset” à 14h00 the indicator

     

    Thank you for your help

     

    Have a perfect day

    #86444

    It seems easy to reset a variable to 0 or whatever other value, so I don’t think that’s the main reason of your question? Do you still use the value “ok / not ok” of the morning period but in the afternoon? BTW, would be easier and faster to understand and reply with the code.

    #86446

    Hello Nicolas,

     

    You’re right, it’s better with code 😉

    here an example of code I posted few days ago (the logic is the same):

    So, this morning, atrmax was 29 in UT1. So no pb for me, the market’spsychology is OK with that ATR. But, during lunch time, it’s not the same thing. And I wanted to “resest” the indicator with atrmax begining at 12h00, not 00h00.

     

    Hope that I explain this clearly 😉

     

    Thank you for your help Nicolas.

     

    Have a perfect day.

    #86449

    If I could code this I’ll do:

    So, if the value atrmax is X between 00h00 and 12h00, the code do the formula with X value.

    And if the  value atrmax is Y between 12h00 and 23h59, the code do the formula with Y value.

    #86454

    This is what you need:

    The period is a subtraction between the current barindex and the one saved when you want the period of calculation to start, at the beginning of the day or at 120000.

    #86461

    Thank you Nicolas for your quick and perfect answer.

     

    Have a perfet day.

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