TSI Strategy Automation

• 09/09/2019 at 10:31 AM #106921
  RiaanvN

  Hello,

  I require assistance please? I have basic strategy which I wish to automate but unfortunately the True Strength Indicator is “not available in ProBuilder language”. I have been using the the following code obtained from a previous forum:

  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close))))) TSI = 100 * (a/b)

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  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close)))))   TSI = 100 * (a/b)

  Please will you assist with code for TSI(1) and TSI(2)?

  This is my strategy:

  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close))))) TSI = 100 * (a/b) // Conditions to enter long positions c1 = TSI < -20 c2 = TSI > TSI(1) and TSI(1)>TSI(2) IF c1 and c2 THEN BUY 1 lot AT MARKET ENDIF

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  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close)))))   TSI = 100 * (a/b)   // Conditions to enter long positions c1 = TSI < -20 c2 = TSI > TSI(1) and TSI(1)>TSI(2)   IF c1 and c2 THEN BUY 1 lot AT MARKET ENDIF

  Thanks

   

  

  RiaanvN

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  09/09/2019 at 11:25 AM #106927
  robertogozzi

  > For clarity of messages on ProRealCode’s forums, please use the “insert code PRT” button to separate the text of the code part! Thank you! <<

  At line 8 replace parenthesis with brackets to get  TSI[1] & TSI[2].

  1 user thanked author for this post.

  RiaanvN

  

  robertogozzi

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  09/09/2019 at 11:32 AM #106929
  RiaanvN

  Ai, silly me. Thanks Roberto.

  

  RiaanvN

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  04/22/2020 at 9:35 PM #127524
  Bulle

  Hello, i am wondering how do we write a[1] in this exemple?

  Is it this?

  a[1] = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))[1]

  1	a[1] = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))[1]

   

  

  Bulle

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  04/22/2020 at 10:36 PM #127526
  Vonasi

  Please use the ‘Insert PRT Code’ button when putting any code in your posts.

  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))

  1	a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))

  defines what the value of ‘a’ is for every bar.

  a[1] on its own will just return the value for ‘a’ one bar back from the last bar on the chart.

   

  

  Vonasi

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  04/22/2020 at 11:27 PM #127527
  Bulle

  Thanks for your answer so a[1] should be this right?

  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) a[1] = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))

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  a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))   a[1] =  (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))

  Thanks for your answer so a[1] should be this right?

  I ask this because i want to find the close X such as

  (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))-(ExponentialAverage[13](ExponentialAverage[25](ROC[1](X))))=0

  1	(ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))-(ExponentialAverage[13](ExponentialAverage[25](ROC[1](X))))=0

  Do you have a way to calculate that X?

  

  Bulle

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  04/23/2020 at 12:46 AM #127532
  robertogozzi

  You cannot assign a value to a past event.

  a[1] is the result of an assignment occurred the previous candle and is read-only.

   

  

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