TSI Strategy Automation

RiaanvN · 2019-09-09T09:31:37+00:00

Hello, I require assistance please? I have basic strategy which I wish to automate but unfortunately the True Strength Indicator is “not available in ProBuilder language”. I have been using the the following code obtained from a previous forum: a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close))))) TSI = 100 * (a/b) Please will you assist with code for TSI(1) and TSI(2)? This is my strategy: a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close)))) b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close))))) TSI = 100 * (a/b) // Conditions to enter long positions c1 = TSI TSI(1) and TSI(1)>TSI(2) IF c1 and c2 THEN BUY 1 lot AT MARKET ENDIF Thanks

Viewing 7 posts - 1 through 7 (of 7 total)

Author

Posts
09/09/2019 at 10:31 AM #106921 quote
RiaanvN
Participant

Average
Hello,

I require assistance please? I have basic strategy which I wish to automate but unfortunately the True Strength Indicator is “not available in ProBuilder language”. I have been using the the following code obtained from a previous forum:
```
a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))
b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close)))))

TSI = 100 * (a/b)
```
Please will you assist with code for TSI(1) and TSI(2)?

This is my strategy:
```
a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))
b = (ExponentialAverage[13](ExponentialAverage[25](ABS(ROC[1](close)))))

TSI = 100 * (a/b)

// Conditions to enter long positions
c1 = TSI < -20
c2 = TSI > TSI(1) and TSI(1)>TSI(2)

IF c1 and c2 THEN
BUY 1 lot AT MARKET
ENDIF
```
Thanks
09/09/2019 at 11:25 AM #106927 quote

robertogozzi
Moderator

Legend

> For clarity of messages on ProRealCode’s forums, please use the “insert code PRT” button to separate the text of the code part! Thank you! <<

At line 8 replace parenthesis with brackets to get TSI[1] & TSI[2].

RiaanvN thanked this post

09/09/2019 at 11:32 AM #106929 quote

RiaanvN
Participant

Average

Ai, silly me. Thanks Roberto.

04/22/2020 at 9:35 PM #127524 quote
Bulle
Participant

New
Hello, i am wondering how do we write a[1] in this exemple?

Is it this?
```
a[1] = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))[1]
```
04/22/2020 at 10:36 PM #127526 quote
Vonasi
Moderator

Master
Please use the ‘Insert PRT Code’ button when putting any code in your posts.
```
a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))
```
defines what the value of ‘a’ is for every bar.

a[1] on its own will just return the value for ‘a’ one bar back from the last bar on the chart.
04/22/2020 at 11:27 PM #127527 quote
Bulle
Participant

New
Thanks for your answer so a[1] should be this right?
```
a = (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close))))

a[1] =  (ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))
```
Thanks for your answer so a[1] should be this right?

I ask this because i want to find the close X such as
```
(ExponentialAverage[13](ExponentialAverage[25](ROC[1](close[1]))))-(ExponentialAverage[13](ExponentialAverage[25](ROC[1](X))))=0
```
Do you have a way to calculate that X?
04/23/2020 at 12:46 AM #127532 quote

robertogozzi
Moderator

Legend

You cannot assign a value to a past event.

a[1] is the result of an assignment occurred the previous candle and is read-only.
Author

Posts