Need help with arrays to count highs and lows with conditions

• 12/15/2020 at 12:27 AM #153777
  jebus89

  Im not sure if its correct to make a request for help here or to use niclas’ thread so please move my post if you feel like it mods.

  Im fairly new with PRT v11 arrays and im trying to wrap my head around it. Would love to get some help.
  I wanna start with something fairly simple. Please look at attached screenshot for details.

  So for starters i want to do 2 things:

  1. Count as explained in the photo. Count the amount of highs and count the amount of lows, seperatly.
  2. I want to be able to use the price of the different levels. Lets for example say that my system demands a count higher than 3, and i want to buy if low closes under point 2.

  And im not begging for the code here, a walkthrough on how to do it would be amazing, so i dont have to bother you guys forever 🙂 Teach a man to fish etc!

   

  Edit: btw the photo is daily candles on amazon in end of July month 2020

  Edit2: If im wrong about the numbers in the index its because i dont quite understand it yet! Or i might have botched a copy paste 🙂 in other words, i might be wrong

   

  

  jebus89

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  12/15/2020 at 8:52 AM #153795
  Nicolas

  Firstly, are you able to code the conditions you describe to detect the counts? (before using arrays to store them).

  

  Nicolas

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  12/19/2020 at 11:32 PM #154496
  jebus89

  i assume i would need to start with

  if high crosses over highest[period1](high[1]) then

  1	if high crosses over highest[period1](high[1]) then

  This would be the trigger to start the count. As long as there is no higher high then that point then the count continues. I would also need to stop the count if it breaks to the downside. I think that point would have to be low crosses under lowest[period2] from the highest high point.

  After that i would code in the lower low/higher highs

  If low crosses under lowest[period](low[1]) and low > lowest-low-period-before-highest-high-that-started-count then if high crosses over highest[period](high[1]) and high < highest-high-that-started-count then

  1 2 3

  If low crosses under lowest[period](low[1]) and low > lowest-low-period-before-highest-high-that-started-count then   if high crosses over highest[period](high[1]) and high < highest-high-that-started-count then

   

  

  jebus89

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  12/19/2020 at 11:38 PM #154498
  jebus89

  I ment to say in the pictures last text: “New highest high, count is now reset”

  

  jebus89

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  12/22/2020 at 1:57 AM #154808
  jebus89

  Maybe this will help with showing what level of understanding im at..

  a1 = 0 b1 = 0 c1 = 0 d1 = 0 abcd = 0 $var[0] = highest[50](high[1]) // highest high past 150 bars $var[1] = highest[30](high)[15] //highest high past 50 bars from 30 bars ago $var[2] = highest[15-1](high)[1] //highest high past 30 bars $varlow[0] = lowest[80](low) // highest high past 150 bars $varlow[1] = lowest[30](low)[15] //highest high past 50 bars from 30 bars ago $varlow[2] = lowest[15-1](low)[1] //highest high past 30 bars a = $var[0] > $var[2] b = $var[1] > $var[2] c = $varlow[0] < $varlow[1] and $varlow[0] < $varlow[2] d = $varlow[1] > $varlow[2] if a then a1 = 1 endif if b then b1 = 1 endif if c then c1 = 1 endif if d then d1 = 1 endif if a and b and c and d then abcd = 2 endif return a1 as "a" ,b1 as "b" ,c1 as "c" ,d1 as "d", abcd as "abcd down!"

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38

  a1 = 0 b1 = 0 c1 = 0 d1 = 0 abcd = 0   $var[0] = highest[50](high[1]) // highest high past 150 bars $var[1] = highest[30](high)[15] //highest high past 50 bars from 30 bars ago $var[2] = highest[15-1](high)[1] //highest high past 30 bars   $varlow[0] = lowest[80](low) // highest high past 150 bars $varlow[1] = lowest[30](low)[15] //highest high past 50 bars from 30 bars ago $varlow[2] = lowest[15-1](low)[1] //highest high past 30 bars     a = $var[0] > $var[2] b = $var[1] > $var[2] c = $varlow[0] < $varlow[1] and $varlow[0] < $varlow[2] d = $varlow[1] > $varlow[2]   if a then a1 = 1 endif if b then b1 = 1 endif if c then c1 = 1 endif if d then d1 = 1 endif   if a and b and c and d then abcd = 2 endif   return a1 as "a" ,b1 as "b" ,c1 as "c" ,d1 as "d", abcd as "abcd down!"

   

  

  jebus89

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  12/22/2020 at 10:36 AM #154867
  Vonasi

  You don’t really need to use arrays if you just want to record the last highest high and last lowest low and perhaps the ones before that. Think of arrays as a big filing cabinet that you can store lots of information in to later search through easily. If you only have a couple of bits of paper to store then you don’t need to use a filing cabinet – a couple of envelopes will do.

  

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  12/22/2020 at 11:04 AM #154873
  jebus89

  yea i get that Vonasi, im just trying to understand this using a practical example that i can do.. i guess i picked a bad example tho. Im not sure how the lastset stuff and looping work.

  

  jebus89

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  01/13/2021 at 3:39 PM #157665
  Nobody

  Some of the best most useful threads in PRC are the ones with tumbleweeds imo  . Post an uber optomised no logic curve and the crowd flocks in .  Never ceases to amaze me  .

   

  Profit is onto something with his ” count ” imo   .  Add some volatility filter  and  couple more simple parameters and you got a ” thing ”

   

  rock on  and yeah its cryptic

  

  Nobody

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