ma=average[20](close)
timeframe(monthly)
m1=ma>1
timeframe(weekly)
w1=ma>1
timeframe(daily)
d1=ma>1
SCREENER [m1 and w1 and d1]
Should variable ma=average[20](close)
be positioned within the relevant timeframe(s) or can it be situated at the top of the code outside of the timeframes?
JSParticipant
Veteran
This allows you to display the different averages in the graph with the lowest time frame…
timeframe(daily)
ma=average[20](close)
timeframe(weekly)
ma1=average[20](close)
timeframe(monthly)
ma2=average[20](close)
Return ma, ma1, ma2
This allows you to screen whether the “close” (lowest time frame) is larger than the different average:
timeframe(daily)
C1=Close>average[20](close)
timeframe(weekly)
C2=Close>average[20](close)
timeframe(monthly)
C3=Close>average[20](close)
Screener[ c1 and c2 and c3]
ma=average[20](close)
timeframe(monthly)
m1=ma>1
timeframe(weekly)
w1=ma>1
timeframe(daily)
d1=ma>1
SCREENER [m1 and w1 and d1]
or
timeframe(monthly)
ma=average[20](close)
m1=ma>1
timeframe(weekly)
ma=average[20](close)
w1=ma>1
timeframe(daily)
ma=average[20](close)
d1=ma>1
SCREENER [m1 and w1 and d1]
JSParticipant
Veteran
What do you mean by “ma>1″…?
The moving average (ma) is always greater than 1…
“The moving average (ma) is always greater than 1…”
The condition being tested is not really of importance here, rather I am seeking clarification as to whether the indicator (in this case average[20](close)) can be positioned once above the timeframe() coding or within each timeframe seperately?
JSParticipant
Veteran
I’ve already shown you that…
timeframe(daily)
C1=Close>average[20](close)
timeframe(weekly)
C2=Close>average[20](close)
timeframe(monthly)
C3=Close>average[20](close)
Screener[ c1 and c2 and c3]
Long break i know….
I’ve already shown you that…
with respect you didn’t
Can your code above be rewritten thus
ma20=average[20](close)
timeframe(daily)
C1=Close>ma20
timeframe(weekly)
C2=Close>ma20
timeframe(monthly)
C3=Close>ma20
Screener[ c1 and c2 and c3]
Thanks in advance
be positioned within the relevant timeframe(s) or can it be situated at the top of the code outside of the timeframes?
code placed outside of the timeframes is considered part of the default timeframe, same as inside the
timeframe(default).
JSParticipant
Veteran
The timeframe of the graph is the “default timeframe” …
When it comes to a screener, the “default” timeframe” is the “period” you can set in the ProScreener window…