Is there any way to code and find out the timestamp?

• 02/24/2022 at 4:35 PM #188776
  Suzu Yuk

  Hello,

  Does anyone know how to scan the highest high and lowest low cycle frequency is getting shorter or longer? Please see attached picture.

  I would like to find a timestamp (say X1, X2, X3,,,,,) for each highest high and lowest low. Then (X2 – X1) can tell us how long it took to make each price cycle. By comparing  (X2 – X1)  and  (X3 – X2), I can say whether the price cycle is getting longer or shorter.

  Regards,

  

  Suzu Yuk

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  02/24/2022 at 6:07 PM #188785
  robertogozzi

  Try this (not tested):

  p = 40 x3 = highest[p](high) x2 = highest[p](high[p]) x1 = highest[p](high[p * 2]) For i = (p*3)-1 downto (p*2) if high[i] = x1 then b1 = BarIndex[i] Break Endif Next For i = (p*2)-1 downto p if high[i] = x2 then b2 = BarIndex[i] Break Endif Next For i = p-1 downto 0 if high[i] = x3 then b3 = BarIndex[i] Break Endif Next x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then x = 1 Elsif x1x2 < x2x3 then x = 2 Endif Screener[x](x as “1=x1x2, 2=x2x3")

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  p  = 40 x3 = highest[p](high) x2 = highest[p](high[p]) x1 = highest[p](high[p * 2]) For i = (p*3)-1 downto (p*2)    if high[i] = x1 then       b1 = BarIndex[i]       Break    Endif Next For i = (p*2)-1 downto p    if high[i] = x2 then       b2 = BarIndex[i]       Break    Endif Next For i = p-1 downto 0    if high[i] = x3 then       b3 = BarIndex[i]       Break    Endif Next x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then    x = 1 Elsif x1x2 < x2x3 then    x = 2 Endif Screener[x](x as “1=x1x2,  2=x2x3")

   

  

  robertogozzi

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  02/24/2022 at 6:21 PM #188789
  Nicolas

  The new instruction HighestBars could help in this case.

  

  Nicolas

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  02/24/2022 at 11:58 PM #188803
  robertogozzi

  This is the code with the new instruction suggested by Nicolas:

  p = 40 b3 = highestbars[p](high) b2 = highestbars[p](high[p]) b1 = highestbars[p](high[p * 2]) x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then x = 1 Elsif x1x2 < x2x3 then x = 2 Endif Screener[x](x as “1=x1x2, 2=x2x3")

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  p  = 40 b3 = highestbars[p](high) b2 = highestbars[p](high[p]) b1 = highestbars[p](high[p * 2]) x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then    x = 1 Elsif x1x2 < x2x3 then    x = 2 Endif Screener[x](x as “1=x1x2,  2=x2x3")

  

  robertogozzi

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  03/01/2022 at 7:37 PM #189153
  Suzu Yuk

  Thank you very much for your swift reply. I have been tucking to understand the following part of the previously mentioned solution by dissecting the last few days. However, I am still stuck with understanding the below:

  highestbars

  b3 = highestbars[p](high) b2 = highestbars[p](high[p])

  1	b3 = highestbars[p](high) b2 = highestbars[p](high[p])

  I understand “b3 = highestbars[p](high),” but I am not sure if I understand “b2 = highestbars[p](high[p]).” Why :[p](high[p]?” Why “p” in those two places?

  In order to dissect  and understand them on cash 500, ticker “SPTRD,” I program them to print out the code with two variable periods “p1” and “p2.”

  printout version

  p1=4 p2=4 b3 = highestbars[p1](high) DRAWTEXT("#b3#", barindex, high+range*2, Dialog, Standard, 10) COLOURED(255,0,0) b2 = highestbars[p1](high[p2]) //DRAWTEXT("#Hp2#", barindex, high+range*0.6, Dialog, Standard, 12) DRAWTEXT("#b2#", barindex, high+range*1.4, Dialog, Standard, 12)COLOURED(0,0,0) b1 = highestbars[p1](high[p2 * 2]) //x1x2 = b2 - b1 //x2x3 = b3 - b2 //x = 0 //If x1x2 > x2x3 then //x = 1 //Elsif x1x2 < x2x3 then //x = 2 //Endif return

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  p1=4 p2=4 b3 = highestbars[p1](high) DRAWTEXT("#b3#", barindex, high+range*2, Dialog, Standard, 10) COLOURED(255,0,0) b2 = highestbars[p1](high[p2]) //DRAWTEXT("#Hp2#", barindex, high+range*0.6, Dialog, Standard, 12) DRAWTEXT("#b2#", barindex, high+range*1.4, Dialog, Standard, 12)COLOURED(0,0,0) b1 = highestbars[p1](high[p2 * 2]) //x1x2 = b2 - b1 //x2x3 = b3 - b2 //x = 0 //If x1x2 > x2x3 then //x = 1 //Elsif x1x2 < x2x3 then //x = 2 //Endif return

  If anyone can possibly rephrase them in words, I would highly appreciate it very much.

  

  Suzu Yuk

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  03/01/2022 at 9:31 PM #189164
  robertogozzi

  This line will check a highest value among the latest p bars (from 0 to 39):

  highestbars[p](high)

  1	highestbars[p](high)

  you need two prior additional ones to find all the three, one between bars 40-79 and the leftmost one between bars 80-119.

  You can evaluate the expressions within brackets to check that.

   

  

  robertogozzi

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  03/03/2022 at 9:19 AM #189225
  Suzu Yuk

  Thank you very much for your reply. In order to understand what is going on with the code, I quantified the changing output with the gradation of color on cash 500, ticker symbol “SPTRD, screenshot attached. Would anyone agree with me the below:

  The blue gradation seems to illustrate the price cycle to be getting shorter.

  The black gradation seems to illustrate the price cycle to be getting longer.

  I am not sure yet if I can conclude as the above. I appreciate it very much if I can hear how other people can observe this outcome? Thank you

  p=4
  b3 = highestbars[p1](high)
  //DRAWTEXT(“#b3#”, barindex, high+range*2, Dialog, Standard, 10) COLOURED(255,0,0)
  Hp2=high[p2]
  b2 = highestbars[p1](high[p1])
  //DRAWTEXT(“#Hp2#”, barindex, high+range*0.6, Dialog, Standard, 12)
  //DRAWTEXT(“#b2#”, barindex, high+range*1.4, Dialog, Standard, 12)COLOURED(0,0,0)
  b1 = highestbars[p1](high[p1 * 2])
  //DRAWTEXT(“#b1#”, barindex, high+range*0.7, Dialog, Standard, 12)COLOURED(0,0,255)
  x1x2 = b2 – b1
  x2x3 = b3 – b2
  x = 0
  If x1x2 > x2x3 then
  M1 = x1x2 – x2x3
  HiM1=highest[pM1](M1)
  DRAWTEXT(“▇”, barindex, 1.001*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,255, 255*M1/HiM1)
  x = 1
  Elsif x1x2 < x2x3 then
  M2 = -x1x2 + x2x3
  HiM2=highest[pM1](M2)
  DRAWTEXT(“▇”, barindex, 1.002*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,0, 255*M2/HiM2)
  x = 2
  Endif
  return

  

  Suzu Yuk

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  Been thanked: 2 times
  03/03/2022 at 10:46 AM #189229
  Suzu Yuk

   

  color gradation on cash 500 1 hour 50000units, ticker “SPTRD

  p1=170 p2=170 pM1=170 Hip=211 b3 = highestbars[p1](high) //DRAWTEXT("#b3#", barindex, high+range*2, Dialog, Standard, 10) COLOURED(255,0,0) Hp2=high[p2] b2 = highestbars[p1](high[p1]) //DRAWTEXT("#Hp2#", barindex, high+range*0.6, Dialog, Standard, 12) //DRAWTEXT("#b2#", barindex, high+range*1.4, Dialog, Standard, 12)COLOURED(0,0,0) b1 = highestbars[p1](high[p1 * 2]) //DRAWTEXT("#b1#", barindex, high+range*0.7, Dialog, Standard, 12)COLOURED(0,0,255) x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then M1 = x1x2 - x2x3 HiM1=highest[pM1](M1) DRAWTEXT("▇", barindex, 1.001*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,255, 255*M1/HiM1) x = 1 Elsif x1x2 < x2x3 then M2 = -x1x2 + x2x3 HiM2=highest[pM1](M2) DRAWTEXT("▇", barindex, 1.002*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,0, 255*M2/HiM2) x = 2 Endif return

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  p1=170 p2=170 pM1=170 Hip=211 b3 = highestbars[p1](high) //DRAWTEXT("#b3#", barindex, high+range*2, Dialog, Standard, 10) COLOURED(255,0,0) Hp2=high[p2] b2 = highestbars[p1](high[p1]) //DRAWTEXT("#Hp2#", barindex, high+range*0.6, Dialog, Standard, 12) //DRAWTEXT("#b2#", barindex, high+range*1.4, Dialog, Standard, 12)COLOURED(0,0,0) b1 = highestbars[p1](high[p1 * 2]) //DRAWTEXT("#b1#", barindex, high+range*0.7, Dialog, Standard, 12)COLOURED(0,0,255) x1x2 = b2 - b1 x2x3 = b3 - b2 x = 0 If x1x2 > x2x3 then M1 = x1x2 - x2x3 HiM1=highest[pM1](M1) DRAWTEXT("▇", barindex, 1.001*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,255, 255*M1/HiM1) x = 1 Elsif x1x2 < x2x3 then M2 = -x1x2 + x2x3 HiM2=highest[pM1](M2) DRAWTEXT("▇", barindex, 1.002*highest[Hip](high), Dialog, Standard, 12)COLOURED(0,0,0, 255*M2/HiM2) x = 2 Endif return

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  Suzu Yuk

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