Increment a Value Failure – Infinite Loops

• 06/25/2018 at 12:14 PM #74307
  JonnyBoy

  Hi Everybody,

  I’ve used the forum as a guest for a long time but first post.

  I am trying to build an indicator that increments a value everytime (eachbar) that the IF statement is TRUE and de-increments the value on each bar it is FALSE.

  So for example if the condition had been TRUE for 5 bars the value would equal 5, then if the next bar was FALSE value = 4 and so on.

  Attempt 1 – using IF statements:

  Attempt 1

  IF LOW > LowPointave THEN LowAdd = LowAdd + 1 ELSE LowAdd = LowAdd - 1 ENDIF

  1 2 3 4 5

  IF LOW > LowPointave THEN LowAdd = LowAdd + 1 ELSE LowAdd = LowAdd - 1 ENDIF

  Result was the indicator just flipped between 1 and -1.

   

  Attempt 2 – Using Loops

  attempt 2

  IF LOW > LowPointave THEN i = 1 ELSE i = 0 ENDIF LowAdd = 0 WHILE i = 1 DO LowAdd = LowAdd + 1 WEND

  1 2 3 4 5 6 7 8 9 10

  IF LOW > LowPointave THEN i = 1 ELSE i = 0 ENDIF   LowAdd = 0 WHILE i = 1 DO LowAdd = LowAdd + 1 WEND

   

  Result – “An infinite loop or loop with too many iterations was detected….”

   

  What does this mean and is there any way I can meet my goal?

   

  Thanks kindly ,

   

  Jon

   

  

  JonnyBoy

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  06/25/2018 at 12:42 PM #74308
  Vonasi

  Your first example works. I tested this:

  LowPointave = average[200](low) IF LOW > LowPointave THEN LowAdd = LowAdd + 1 ELSE LowAdd = LowAdd - 1 ENDIF return lowadd

  1 2 3 4 5 6 7 8 9

  LowPointave = average[200](low)   IF LOW > LowPointave THEN LowAdd = LowAdd + 1 ELSE LowAdd = LowAdd - 1 ENDIF   return lowadd

  and got this:

  

  So it must be whatever your LowPointAve is that is the problem.

  

  Vonasi

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  06/25/2018 at 2:03 PM #74322
  Nicolas

  You are stuck in the loop between lines 4 and 8,  it will never break because your variable i remains 1 infinitely…

  

  Nicolas

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