there are 2 ways:

MyHighest = highest[10](high)[10]
MyLowest = lowest[10](low)[10]

Ampli = MyHighest - MyLowest

myHi=0
myLo=9999999
for i=10 to 19 do
   if high[i]>myHi then
      myHi=high[i]
      myHix=barindex[i]
   endif
   if low[i]<myLo then
      myLo=low[i]
      myLox=barindex[i]
   endif
next
amp=myHi-myLo

print amp as "Loop"
print Ampli
return

Yes! first option

The 10 on the far left means that the search is for the highest price of the last 10 periods.
The 10 on the far right means you want to retrieve what the scan reported 10 bars ago.

MyHighest = highest[10](high)[10]

It is equivalent to writing:

MyHighest1 = highest[10](high)
MyHighest2 = MyHighest1[10]

I would like to point out that your line is NOT scanning for the highest price, but for the highest CLOSE, since you didn’t specify what to scan and so it defaults to CLOSE:

MyHighest = highest[10](high) //MyHighest = highest[10] verwendet standardmäßig CLOSE

Hi,

You are using the instruction syntax correctly; however, you need to take into account that the instruction works with bars rather than dates…

The number of bars does not correspond one-to-one with calendar days due to holidays and weekends…

A bar represents a trading day, and on holidays and weekends the market is closed…

thomas2004ch wrote:

Thanks!

In order to better understand what you said, here an example: Today is 13.12.2025. If I want to find the highst high between 01.12.25 and 05.12.2025, I have to do as follow?

MyHighest = highest[5](high)[8]

Your line retrieves the highest price in a 5-day range, starting from the 8th bar prior to the current day (see attached pic).

x-3.jpg

Hi Roberto,

I think the picture is not correct because December 6 and 7 fall on a weekend, so no bars are created on those days…

Based on the actual trading bars…

MyHighest = Highest[5](High)[6]