How to exit from position

enzo_52 · 2017-06-28T13:11:03+00:00

// Definizione dei parametri del codice DEFPARAM CumulateOrders = False // Posizioni cumulate disattivate ID = high low[1] if ID then test = 1 hh = highest[2](high) ll = lowest[2](low) endif if test = 1 then if time>=110000 and time =020000 and time = 020000 and time =110000 and time<=120000 then EXITSHORT AT hh STOP test = 0 endif

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06/28/2017 at 2:11 PM #39306 quote
enzo_52
Participant

Senior
```
// Definizione dei parametri del codice
DEFPARAM CumulateOrders = False // Posizioni cumulate disattivate

ID = high<high[1] and low>low[1]

if ID then
test = 1
hh = highest[2](high)
ll = lowest[2](low)

endif

if test = 1 then
if time>=110000 and time <=120000 then
BUY 1 SHARE AT hh STOP
endif
endif

if test=1 then
if time>=020000 and time <=050000 then
sellshort 1 SHARE AT ll STOP
endif
endif

if longonmarket and time >= 020000 and time<=050000then
SELL AT ll STOP

test = 0
endif

if shortonmarket and time>=110000 and time<=120000 then
EXITSHORT AT hh STOP

test = 0
endif
```
06/28/2017 at 2:14 PM #39307 quote

enzo_52
Participant

Senior

hi guys, i need help for to exit from long position or short position olso when the condition hh or ll do is not verified, i want exit ,if long at 050000, if short at 120000

thanks

06/28/2017 at 2:43 PM #39315 quote

Nicolas
Keymaster

Legend

Wrong section of forum once again Enzo, please try to post to the correct section next time (ProOrder for automated strategy). Thank you. 👿

Basically, you want your stoploss to be the size of the hh-ll range?

06/29/2017 at 4:47 PM #39424 quote

enzo_52
Participant

Senior

Apologyse Nicolas, You are righe… Forgive me

06/29/2017 at 5:01 PM #39426 quote
Nicolas
Keymaster

Legend
So if the answer to my question is “yes”, just use the SET STOP LOSS function with the hh-ll range, like this:
```
SET STOP LOSS (hh-ll)
```
06/30/2017 at 1:01 PM #39481 quote

enzo_52
Participant

Senior

Hi Nicolas, no , the sell and exitshort signals are with 1 condiction: SELL AT ll STOP , EXITSHORT AT hh STOP, i want that if the price do not touch LL or HH level the trade long or short .stops.

if i am long close at 05 o clock , if i am short close at 12 o clock

i hope i was clear ..

thanks

06/30/2017 at 3:50 PM #39513 quote
Nicolas
Keymaster

Legend
Hmmm… I think we are lost in translation here 🙂

Ok, so now if you want to exit your long position at 5 o’clock, let’s code it like this:
```
if time=050000 and longonmarket then 
 sell at market 
endif
```
and do the opposite for your short orders.
06/30/2017 at 6:52 PM #39521 quote

enzo_52
Participant

Senior

sorry for my english..be patient Nicolas :-),

i want that my long position will be close if in 02 to 05 o clock or at condition “LL” or if this condition is not verified i want close my long position at 05 o clock.

the same thing for short position

thanks so much Nicolas

07/01/2017 at 7:57 PM #39563 quote
enzo_52
Participant

Senior
```
hh = highest[4](high)
if time>=020000 and time<=050000 and shortonmarket then

EXITSHORT 1 share  AT hh  stop
elsif  time=050000 then
exitshort 1 share at market

endif
```
it do is not work…. Why?

thanks
07/03/2017 at 9:19 AM #39645 quote
Nicolas
Keymaster

Legend
Are you sure your “hh” level is below the current Close? I don’t think that possible. You should look 1 period ago instead, like this:
```
hh = highest[4](high)

if time>=020000 and time<050000 and shortonmarket then
 EXITSHORT 1 share  AT hh[1]  stop
endif

if shortonmarket and time=050000 then 
 exitshort at market
endif
```
07/03/2017 at 11:34 AM #39670 quote

enzo_52
Participant

Senior

hh is a condition, if the price do is not go upper the “hh” the trade continue to be short , but anyway at 050000 must be closed.

if the price go is upper the hh between 020000 – 050000 then i want that trade must be closed

i hope to be clear

sorry for my english 🙂

07/03/2017 at 1:06 PM #39686 quote

Nicolas
Keymaster

Legend

ok it’s clear, so the code posted in my previous message should work as intended.

07/03/2017 at 3:42 PM #39707 quote
enzo_52
Participant

Senior
```
ID = high<high[1] and low>low[1]
rang = range
NR4 = rang<range[1] and rang<range[2] and rang<range[3]
 
if ID and NR4 then
test = 1
hh = highest[4](high)
ll = lowest[4](low)
endif
```
```
ID = high<high[1] and low>low[1]
rang = range
NR4 = rang<range[1] and rang<range[2] and rang<range[3]
 
fi= ID and NR4

hh = highest[4](high)
ll = lowest[4](low)
```
what do is it mean 1st code…and what is the difference ?
07/03/2017 at 3:42 PM #39708 quote

enzo_52
Participant

Senior

no, Niclosa it do is not work

help me. please

07/05/2017 at 10:40 AM #39860 quote

enzo_52
Participant

Senior

Hello Nicolas ,

when you have time , please try to answer me

Thanks a lot
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