How can I code a line (x1,y1,x2,y2)?

• 11/27/2018 at 7:44 PM #85857
  ligand

  Sorry if this is redundant. I don’t succeed to code a line y=mx+n, defined by 4 known parameters x1,y1,x2,y2. My aim ist to code for example a buy order if close crosses under a certain line (which can be described mathematically with y=((y2-y1)/(x2-x1))x + y1-((y2-y1)x1/(x2-x1))).

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  11/27/2018 at 7:45 PM #85858
  ligand

  Vronasi suggested that perhaps Nicolas or juanj know the answer.

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  11/27/2018 at 8:35 PM #85860
  Vonasi

  Please don’t double post.

  If you have not received an answer then patience is better than having two topics on the same subject. If you have waited a long time for an answer then maybe it is because no one knows the answer! Sometimes a little polite reminder on the original thread can bump it back to the top and maybe get your answer. Double posting leads to confusion and wasted time for those trying to help.

  

  Vonasi

  Moderator

  Topics: 192

  Replies: 5088

  Been thanked: 1810 times
  11/27/2018 at 8:35 PM #85861
  GraHal

  @ligand … you know you can draw a line on a Chart and set an alert and / or trade if price crosses under / over this line?

  I know this is not what you mean, but thought I’d mention it in case you may be able to use the above easy method re prices crossing lines to prove whether your y=mx+c coded strategy is worth pursuing?

  

  GraHal

  Participant

  Topics: 204

  Replies: 8418

  Been thanked: 2043 times
  11/27/2018 at 8:59 PM #85863
  GraHal

  Anyway can’t you do something similar (to y=mx+c) by considering …

  Price increase > a and < b over c bars represents gradient d Price Line?

  Price increase > e and < f over c bars represents gradient g Price Line?

  Just an idea going round in my head! 🙂

  

  GraHal

  Participant

  Topics: 204

  Replies: 8418

  Been thanked: 2043 times
  11/27/2018 at 10:41 PM #85869
  robertogozzi

  ProOrder only deals with prices, so you must refence a line (S/R)  only by the price it sits on. Line coordinates are used only to draw lines on charts, but cannot be refenced from code.

  1 user thanked author for this post.

  GraHal

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 16472

  Been thanked: 3643 times
  11/28/2018 at 10:48 AM #85896
  Nicolas

  If you can define the distance in price (Y) between 2 bar coordinates (X), then you can calculate the factor.

  

  Nicolas

  Keymaster

  Topics: 81

  Replies: 20828

  Been thanked: 4742 times
  12/01/2018 at 9:57 PM #86165
  ligand

  Thanks for the answers and sorry vronasi – I didn’t know wether I should start an extra question. I won’t do this again.

  If you look at the countertrendlines in the chart below you can see the general idea of the system (for example for a bull market):

  1. Momentum(EMA20-EMA50)>0 on a higher time frame, so the bull is still developing

  2. Define the line between highest(5) and highest(10)

  3. Buy if close crosses over this line

  4. trailing stop 1.5 x length of the crossing bar.

  But if I understand you ok, it is not possible to code for such countertrendlines?

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  12/01/2018 at 10:01 PM #86167
  ligand

  I forgot one criterium:

  5. the countertrendline is not to cross the price ranges of any of the bars involved, just the highest points of for example 5 and 10 bars (optimal values have to be defined by backtesting, which is of course also true for the length of the trailing stop)

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  12/18/2018 at 2:46 PM #87360
  ligand

  If someone is interested, I did it with a little trigonometry and this seems to work, at least as a screener:

   

  breakout on crossing a countertrendline

  y1=lowest[25](low) y2=lowest[10](low) For i=25 downto 0 do IF low[i]=y1 then x1=barindex[i] break endif next For i=10 downto 0 do IF low[i]=y2 then x2=barindex[i] break endif next //Der Punkt auf der Aufwärtslinie wird bestimmt, der vom letzten barclose unterkreuzt werden muss, damit ein Verkaufssignal entsteht x3=barindex[1] y3=y2+((x3-x1)*(y2-y1)/(x2-x1)) //Falls close[1] den Punkt y3 auf der Gegentrend-Aufwärtslinie unterkreuzt, gibt es das Verkaufssignal indicator4=close[1] crosses under y3

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

  y1=lowest[25](low) y2=lowest[10](low) For i=25 downto 0 do IF low[i]=y1 then x1=barindex[i] break endif next For i=10 downto 0  do IF low[i]=y2 then x2=barindex[i] break endif next   //Der Punkt auf der Aufwärtslinie wird bestimmt, der vom letzten barclose unterkreuzt werden muss, damit ein Verkaufssignal entsteht x3=barindex[1] y3=y2+((x3-x1)*(y2-y1)/(x2-x1))   //Falls close[1] den Punkt y3 auf der Gegentrend-Aufwärtslinie unterkreuzt, gibt es das Verkaufssignal indicator4=close[1] crosses under y3

   

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  12/18/2018 at 2:48 PM #87361
  ligand

  I’ve got just one short question:

  How can I find/code the lowest low of the last 10 bars, disregarding the last 2 ones?

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  12/18/2018 at 3:07 PM #87365
  Nicolas

  disregarding the last 2 lowest low? so you want to pick the third one backward?

  

  Nicolas

  Keymaster

  Topics: 81

  Replies: 20828

  Been thanked: 4742 times
  12/18/2018 at 5:39 PM #87386
  ligand

  Exactly, I’m looking for the lowest value of the seven bars, which precede the third last bar (or in other words: the low of the tenth to third last bar). Itl’s obviously not possible to call it something like lowest[10-3](low). I tried to construct a loop but was unable to do so. 🙁

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
  12/18/2018 at 5:59 PM #87390
  Vonasi

  ll = close[2] for a = 2 to 9 ll = min(low[a],ll) next

  1 2 3 4

  ll = close[2] for a = 2 to 9 ll = min(low[a],ll) next

   

  1 user thanked author for this post.

  Nicolas

  

  Vonasi

  Moderator

  Topics: 192

  Replies: 5088

  Been thanked: 1810 times
  12/18/2018 at 8:14 PM #87400
  ligand

  Thanks a lot!

  

  ligand

  Participant

  Topics: 3

  Replies: 27

  Been thanked: 1 time
• Author
  Posts