Higer exponential average

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07/04/2024 at 6:23 PM #234797 quote
Ludde
Participant

New
Hi; I wonder if You can help me with this.

I would like to have a proscreener with the following conditions:
1. An 8-day exponential moving average (EMA) that is turning upwards.
2. The 8-day EMA must also be higher than the last time the 8-day EMA turned upwards.
07/04/2024 at 7:45 PM #234802 quote
robertogozzi
Moderator

Master
There you go:
```
ONCE CurrTurn = 0
ONCE PrevTurn = 0
Cond = 0
Sma8 = average[8](close)
UPturn = (Sma8 > Sma8[1]) AND (Sma8[1] < Sma8[2])
IF UPturn THEN
   PrevTurn = CurrTurn
   CurrTurn = Sma8
   IF CurrTurn > PrevTurn THEN
      Cond = 1
   ENDIF
ENDIF
SCREENER[Cond]
```
Iván González thanked this post
07/06/2024 at 2:07 PM #234840 quote

Ludde
Participant

New

Thank you for helping me, but it doesn´t work for me. I gets all kind of different hits.

07/06/2024 at 6:27 PM #234860 quote
robertogozzi
Moderator

Master
My bad, I incorrectly coded SMA instead of EMA.

This is correct:
```
ONCE CurrTurn = 0
ONCE PrevTurn = 0
Cond = 0
Ema8 = average[8,1](close)
UPturn = (Ema8 > Ema8[1]) AND (Ema8[1] < Ema8[2])
IF UPturn THEN
   PrevTurn = CurrTurn
   CurrTurn = Ema8
   IF CurrTurn > PrevTurn THEN
      Cond = 1
   ENDIF
ENDIF
SCREENER[Cond]
```
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Higer exponential average

ProScreener: Market Scanners & Detection

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Author

Ludde @ludde Participant

Summary

This topic contains 3 replies,
has 2 voices, and was last updated by robertogozzi
1 year, 8 months ago.

Topic Details

Forum:	ProScreener: Market Scanners & Detection
Language:	English
Started:	07/04/2024
Status:	Active
Attachments:	No files

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