GRADIENT IN SMA

steynpj · 2020-05-23T03:47:30+00:00

I would like to code a rough gradient in a moving average. My clumsy idea was to try code the SMA, must be higher than SMA of 5 periods ago plus a value, which is X below. indicator5 = Average[C](close) indicator6 = Average[C](close) c3 = (indicator5 > indicator6[5]+X) Above not working. Help appreciated

Viewing 6 posts - 1 through 6 (of 6 total)

Author

Posts
05/23/2020 at 4:47 AM #132914 quote
steynpj
Participant

Average
I would like to code a rough gradient in a moving average. My clumsy idea was to try code the SMA, must be higher than SMA of 5 periods ago plus a value, which is X below.
```
indicator5 = Average[C](close)
indicator6 = Average[C](close)
c3 = (indicator5 > indicator6[5]+X)
```
Above not working.

Help appreciated
05/23/2020 at 6:32 AM #132916 quote
robertogozzi
Moderator

Legend
Try
```
c3 = (indicator5 - indicator6[5]+X)
```
This could also help https://www.prorealcode.com/reply/70279/
05/23/2020 at 12:00 PM #132936 quote

steynpj
Participant

Average

Thank you.

Does not seem to work

05/23/2020 at 1:42 PM #132945 quote
Vonasi
Moderator

Master
The best way to measure a gradient is with a ratio of y and x.
```
c = 100
x = 5
y = average[c] - average[c](close[x-1])

Ratio = (y/x)
```
Negative ratio results are a downward sloping MA and the lower the number the steeper the angle. Positive ratio results are an upward sloping MA and the greater the number the steeper the angle.
05/23/2020 at 1:48 PM #132947 quote
Vonasi
Moderator

Master
If you convert it to a percentage of the average p bars back then it is even more usable.
```
p = 100 
x = 5 
y = average[p] - average[p](close[x-1]) 
Ratio = ((y/x)/average[p](close[x-1]))*100

return ratio
```
nonetheless and GraHal thanked this post
05/23/2020 at 4:03 PM #132959 quote

GraHal
Participant

Legend

Above added as Log 217 here …

Snippet Link Library
Author

Posts