Comparing Price as condition

Amin1233 · 2024-03-02T03:49:59+00:00

Hi I am trying to write a code to compare the price of previous bars and trigger a flag. what is wrong with this condition? It looks like the close[2]>close[3] doesnt return anything and T always become T=1 at 101000. If time=100000 then T=0 end if If close[2]>close[3] and time>101000 then T=1 Endif

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03/02/2024 at 4:49 AM #229067 quote

Amin1233
Participant

Junior

Hi I am trying to write a code to compare the price of previous bars and trigger a flag. what is wrong with this condition? It looks like the close[2]>close[3] doesnt return anything and T always become T=1 at 101000. If time=100000 then T=0 end if If close[2]>close[3] and time>101000 then T=1 Endif

03/02/2024 at 9:17 AM #229069 quote

GraHal
Participant

Master

It’s probably easier to say, in text, what you want to achieve?

Amin1233 wrote:
close[2]>close[3] doesnt return anything
Abobe returns boolean logic, i.e. either 0 or 1.

Amin1233 wrote:
close[2]>close[3] and time>101000
When close[2]>close[3] is coincident with time>101000 then T will stay at 1 until the next day at 100000 when T will become 0 for a minimum of 1 minute (until this cycle repeats).

03/02/2024 at 10:05 AM #229074 quote

GraHal
Participant

Master

GraHal wrote:
T will become 0 for a minimum of 1 minute
Above should have read … T will become 0 for a minimum of 10 minutes.

03/02/2024 at 10:10 AM #229075 quote

Amin1233
Participant

Junior

I want to have conditions to check if for the last 3 bars the price was closing lower each time and if so then make T=1

03/02/2024 at 11:24 AM #229079 quote
GraHal
Participant

Master
```
T = summation[3](Open>Close)=3
```
03/02/2024 at 12:15 PM #229082 quote
JS
Participant

Master
If you want to check if the last three “closes” where lower, you can also use the following code…

Including the current bar:

Close[0]<Close[1] and Close[1]<Close[2]

Or excluding the current bar:

Close[1]<Close[2] and Close[2]<Close[3]

The code will be (including the current bar):
```
If Time>101000 then
If Close[0]<Close[1] and Close[1]<Close[2] then
T=1
Else
T=0
EndIf
EndIf

Return T as "T"
```
GraHal thanked this post

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03/02/2024 at 3:10 PM #229092 quote

Amin1233
Participant

Junior

when I use the condition in strategy for back testing it doesn’t work.

Close[0]<Close[1] and Close[1]<Close[2] doesn’t return anything The other formula (summation) also not right because i want to compare the closes, there might be a time when close is lower than open but the close is still higher than the privous bar, i need to compare the close of each bar.

03/02/2024 at 3:22 PM #229093 quote
GraHal
Participant

Master
```
T = summation[3](Close<Close[1])=3
```
Above wont ‘return’ anything other than True / 1. But then you might code …
```
If T = 1 Then
SellShort at Market
Endif
```
03/02/2024 at 3:55 PM #229094 quote

JS
Participant

Master

Maybe someone else can help you…

You’re clearly a lot further along when you can judge that the formulas are wrong and not working…

03/02/2024 at 11:46 PM #229121 quote
Amin1233
Participant

Junior
Thanks but still not working. I used the below code:
```
if time=100000 then
TL=0
endif
TL=summation[3](close<close[1])=3

if time>101000 and time<140000 and TL=1 and countoflongshares<2 and close>open[1] then
buy 2 contracts at market 
set stop loss lowest[5]-close+10
endif
if longonmarket and close<open[1] then
sell 2 contracts at market
endif
```
03/03/2024 at 12:44 AM #229122 quote

JS
Participant

Master

The code doesn’t work because you’ve taken a strange combination of conditions…

TL=Summation[3](Close<Close[1])=3 in combination with Close>Open[1]

Try:

if time>101000 and time<140000 and TL=1 and countoflongshares<2 then
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