Comparing Price as condition

• 03/02/2024 at 4:49 AM #229067
  Amin1233

  Hi I am trying to write a code to compare the price of previous bars and trigger a flag. what is wrong with this condition? It looks like the close[2]>close[3] doesnt return anything and T always become T=1 at 101000.

  If time=100000 then

  T=0

  end if

  If close[2]>close[3] and time>101000 then

  T=1

  Endif

  

  Amin1233

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  03/02/2024 at 9:17 AM #229069
  GraHal

  It’s probably easier to say, in text, what you want to achieve?

  Amin1233 wrote:

  close[2]>close[3] doesnt return anything

  Abobe returns boolean logic, i.e. either 0 or 1.

  Amin1233 wrote:

  close[2]>close[3] and time>101000

  When close[2]>close[3] is coincident with time>101000 then T will stay at 1 until the next day at 100000 when T will become 0 for a minimum of 1 minute (until this cycle repeats).

  

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  03/02/2024 at 10:05 AM #229074
  GraHal

  GraHal wrote:

  T will become 0 for a minimum of 1 minute

  Above should have read … T will become 0 for a minimum of 10 minutes.

  

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  03/02/2024 at 10:10 AM #229075
  Amin1233

  I want to have conditions to check if for the last 3 bars the price was closing lower each time and if so then make T=1

  

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  03/02/2024 at 11:24 AM #229079
  GraHal

  T = summation[3](Open>Close)=3

  1	T = summation[3](Open>Close)=3

   

  

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  03/02/2024 at 12:15 PM #229082
  JS

  If you want to check if the last three “closes” where lower, you can also use the following code…

  Including the current bar:

  Close[0]<Close[1] and Close[1]<Close[2]

  Or excluding the current bar:

  Close[1]<Close[2] and Close[2]<Close[3]

  The code will be (including the current bar):

  3 Lower

  If Time>101000 then If Close[0]<Close[1] and Close[1]<Close[2] then T=1 Else T=0 EndIf EndIf Return T as "T"

  1 2 3 4 5 6 7 8 9

  If Time>101000 then If Close[0]<Close[1] and Close[1]<Close[2] then T=1 Else T=0 EndIf EndIf   Return T as "T"

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  GraHal

  

  JS

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  03/02/2024 at 3:10 PM #229092
  Amin1233

  when I use the condition in strategy for back testing it doesn’t work.

  Close[0]<Close[1] and Close[1]<Close[2]  doesn’t return anything 

  The other formula (summation) also not right because i want to compare the closes, there might be a time when close is lower than open but the close is still higher than the privous bar, i need to compare the close of each bar.

  

  Amin1233

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  03/02/2024 at 3:22 PM #229093
  GraHal

  T = summation[3](Close<Close[1])=3

  1	T = summation[3](Close<Close[1])=3

  Above wont ‘return’ anything other than True / 1.

  But then you might code …

  If T = 1 Then SellShort at Market Endif

  1 2 3

  If T = 1 Then SellShort at Market Endif

   

  

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  03/02/2024 at 3:55 PM #229094
  JS

  Maybe someone else can help you…

  You’re clearly a lot further along when you can judge that the formulas are wrong and not working…

  

  JS

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  03/02/2024 at 11:46 PM #229121
  Amin1233

  Thanks but still not working. I used the below code:

  if time=100000 then TL=0 endif TL=summation[3](close<close[1])=3 if time>101000 and time<140000 and TL=1 and countoflongshares<2 and close>open[1] then buy 2 contracts at market set stop loss lowest[5]-close+10 endif if longonmarket and close<open[1] then sell 2 contracts at market endif

  1 2 3 4 5 6 7 8 9 10 11 12

  if time=100000 then TL=0 endif TL=summation[3](close<close[1])=3   if time>101000 and time<140000 and TL=1 and countoflongshares<2 and close>open[1] then buy 2 contracts at market set stop loss lowest[5]-close+10 endif if longonmarket and close<open[1] then sell 2 contracts at market endif

   

  

  Amin1233

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  03/03/2024 at 12:44 AM #229122
  JS

  The code doesn’t work because you’ve taken a strange combination of conditions…

  TL=Summation[3](Close<Close[1])=3 in combination with Close>Open[1]

  Try:

  if time>101000 and time<140000 and TL=1 and countoflongshares<2 then

  

  JS

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