Code of series of periods

• 08/04/2019 at 2:34 PM #104155
  robertogozzi

  All’s well that ends well! 🙂

   

  

  robertogozzi

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  08/04/2019 at 2:51 PM #104157
  GraHal

  robertogozzi wrote:

  All’s well that ends well!

  Maybe not … @maximus78 may have used Roberto code (thinking it was correct / what he needed) and has blown his account … never to be seen again!

  Only teasing! 🙂

  

  GraHal

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  08/04/2019 at 2:55 PM #104158
  robertogozzi

  Yes, but he can refund it and win this time! 🙂

  

  robertogozzi

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  08/04/2019 at 2:57 PM #104159
  robertogozzi

  I know reviving old topics may be dangerous, but keeping an error running is more dangerous!

  

  robertogozzi

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  08/04/2019 at 6:19 PM #104168
  maximus78

  Hello guys, I remember I have verified the code line of Roberto and it was right.

  Now I have verified again in this way and as you can see the results are exactly the same.

  I did an indicator called Maximus with the code of my request:

  a=close>close[1] and close>close[2] and close>close[3] and close>close[4] and close>close[5] if a then result=1 else result=0 endif return result

  1 2 3 4 5 6 7 8 9

  a=close>close[1] and  close>close[2] and close>close[3] and close>close[4] and close>close[5]   if a then result=1 else result=0 endif   return result

  Then i did another indicator called Roberto with his code:

  IF close > highest[5](close[1]) THEN result=1 else result=0 endif return result

  1 2 3 4 5 6 7

  IF close > highest[5](close[1]) THEN result=1 else result=0 endif   return result

  Comparing the results of the binary indicators you see they gives the same results.

  Max

   

  

  maximus78

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  08/04/2019 at 6:37 PM #104173
  Vonasi

  …and the final test. All three in one indicator and output compared. They all do the same thing.

  //maximus a=close>close[1] and close>close[2] and close>close[3] and close>close[4] and close>close[5] if a then result=1 else result=0 endif //roberto IF close > highest[5](close[1]) THEN result2=1 else result2=0 endif //vonasi x = 5 count = 0 for i = 1 to x if close > close[i] then count = count + 1 endif next result3 = 0 if count = x then result3 = 1 endif //final check result4 = result + result2 + result3 flag = 0 if result4 <> 0 and result4 <> 3 then flag = 1 endif return flag

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39

  //maximus a=close>close[1] and  close>close[2] and close>close[3] and close>close[4] and close>close[5]   if a then result=1 else result=0 endif   //roberto IF close > highest[5](close[1]) THEN result2=1 else result2=0 endif   //vonasi x = 5 count = 0 for i = 1 to x if close > close[i] then count = count + 1 endif next result3 = 0 if count = x then result3 = 1 endif   //final check result4 = result + result2 + result3   flag = 0 if result4 <> 0 and result4 <> 3 then flag = 1 endif   return flag

   

  

  Vonasi

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  08/04/2019 at 8:43 PM #104183
  GraHal

  HAHAHAHA … and all that sleep you lost / nightmares Vonasi! 🙂

  Just shows … more than one way to splice the mainbrace eh!

  

  GraHal

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  08/04/2019 at 8:53 PM #104185
  Vonasi

  GraHal wrote:

  more than one way to splice the mainbrace eh!

  …or more than one way to skin a cat….. or more than one way to trip over it in Roberto’s case! 🙂

  

  Vonasi

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  08/04/2019 at 8:54 PM #104186
  robertogozzi

  Yes, the first 3 snippets yield the same results, but not my 4th one (summation).

  So this one is the incorrect one.

  

  robertogozzi

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  08/04/2019 at 9:38 PM #104192
  Vonasi

  robertogozzi wrote:

  but not my 4th one (summation).

  Thank God one of us has finally confirmed that we were wrong – even if it was only 50% wrong! 🙂

  

  Vonasi

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