code for previous low

Probbo63 · 2020-06-22T20:25:16+00:00

Hi Apologies as I’m sure this is a simple piece of code but I can’t seem to work it out. I would like to code for the previous low, but not over a particular number of bars. just however long that previous low is before current price. I’ll then use that to create a signal at 20$% above that. I’ve tried to use: LOWEST [n] (low) but I can’t work out how to allow the flexibility of the time parameter. Thank you for your help.

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06/22/2020 at 9:25 PM #136835 quote

Probbo63
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Hi

Apologies as I’m sure this is a simple piece of code but I can’t seem to work it out.

I would like to code for the previous low, but not over a particular number of bars. just however long that previous low is before current price. I’ll then use that to create a signal at 20$% above that. I’ve tried to use:

LOWEST [n] (low) but I can’t work out how to allow the flexibility of the time parameter.

Thank you for your help.

06/22/2020 at 9:51 PM #136838 quote

robertogozzi
Moderator

Legend

n can be 254 bars maximum, be it on a 1-minute or a 1-week TF.

06/23/2020 at 10:31 AM #136904 quote

Probbo63
Participant

New

Hi

Many thanks. I do understand that, but is there a way I can code for a previous low rather than set a ‘LOWEST’ point determined by a number of bars. Depending on how many bars you set, these 2 methods can give different results. The previous low could be only a few bars before the current bar or it could be 200 bars before, so I don’t want to restrict to a set number of bars. It sounds simple but I’m not sure how to do it.

Many thanks

06/23/2020 at 10:40 AM #136909 quote
robertogozzi
Moderator

Legend
Once you have used
```
MyLow = LOWEST[254](low)
```
to know what price that LOW is, you need an iteration (loop) to scan bars beackwards till you find the right one, which can be 4 or 253 bars away:
```
MyLow = lowest[254](low)
FOR i = 0 TO 253
   IF low[i] = MyLow THEN
      BREAK
   ENDIF
NEXT
```
at the end of the FOR…NEXT loop variable i (counter) will retain the index value of the bar retaining that low, can be 0 if it’s the current bar (LOW[0] or LOW) or any other value up to 253.
06/23/2020 at 11:23 AM #136913 quote

Probbo63
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New

That’s great Roberto, many thanks for your time and help.
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