ACCUMULATED DIFFERENCE

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12/13/2023 at 12:05 PM #225205 quote

twofinger
Participant

New

HI. Need help returning the value “D”.

I am trying to compare todays close with yesterdays for a specific hour, in this case 21000. Then I want to accumulate the difference over time, “D”, with a start value of 100, “ONCE D=100”. But the code will only return the value “100” for “D” and not adding the movement per day.

ONCE D=100
IF TIME=210000 THEN
C=CLOSE
A=(C-C[1])/C[1]//percent movement per day
B=D*A//Value movment per day
D=D+B//Accumulated value over time
ENDIF

RETURN A*100 AS “PROCENT”, B AS “VALUE”, D AS “ACCUMULATE”

12/13/2023 at 12:42 PM #225208 quote
robertogozzi
Moderator

Legend
Try this one:
```
ONCE D=100
IF TIME=210000 THEN
   C=CLOSE
   A=(C-C[1])/C[1]//percent movement per day
   B=D*A//Value movment per day
   D=D+B//Accumulated value over time
ELSE
   X=CLOSE
   A=(X-C)/C//percent movement per day
   B=D*A//Value movment per day
   D=D+B//Accumulated value over time
ENDIF
RETURN A*100 AS "PROCENT", B AS "VALUE", D AS "ACCUMULATE"
```
12/13/2023 at 12:54 PM #225211 quote

twofinger
Participant

New

Thank you but it does not work. Will only show “A” now. Did you try it your self?

Problem it self is probably D=D+B where B should be a fixed value, then it works…

12/13/2023 at 12:59 PM #225212 quote

twofinger
Participant

New

Also, I do only want the 24 hour difference, and not hour by hour: I do want to compare one specific hour with the same hour the day before and then accumulate that difference

Bild-2023-12-13-kl.-12.58.jpeg

12/20/2023 at 3:49 PM #225543 quote
Jean FX
Moderator

Junior
The problem is that we also need to define C on the first candlestick, an example of a quick correction:
```
ONCE D=100
ONCE C=1
IF TIME=210000 THEN
C=CLOSE
A=(C-C[1])/C[1]//percent movement per day
B=D*A//Value movment per day
D=D+B//Accumulated value over time
ENDIF

RETURN A*100 AS "PROCENT", B AS "VALUE", D AS "ACCUMULATE"
```
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