A question about using the summation()

• 01/13/2026 at 11:16 AM #255255
  thomas2004ch

  In the attached screenshot one can see the EMA5 crosses over the EMA10, EMA20 and the EMA50 within the last 5 days. So I wrote the code as follow:

  //P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close) Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4 cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0 cSummation1 = cP11 and cP12 and cP13 return cSummation1

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  //P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close)   Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4   cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0 cSummation1 = cP11 and cP12 and cP13     return cSummation1

  But the RETURN is 0.

  As I just return the cP11 or cP12 or cP13, it is 1.

  Where is my problem?

  

  thomas2004ch

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  01/13/2026 at 12:55 PM #255257
  robertogozzi

  The screener is:

  P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close) Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4 cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0 cSummation1 = cP11 and cP12 and cP13 SCREENER[cSummation1]

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  P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close) Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4 cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0 cSummation1 = cP11 and cP12 and cP13   SCREENER[cSummation1]

  in any case both the indicator and the screener are working as expected.

   

   

   

  

  robertogozzi

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  01/13/2026 at 1:12 PM #255258
  Iván

  Hi! I can’t see it in the attached image.
  Your code is correct. The most likely problem is that all three crossovers are not occurring within the same 5-candle window at the same time.
  I have used this code below to visually see the junctions and I have checked on some assets and it works.
  If you give me details of the ticker, timeframe and date I can check it.

  P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close) Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4 cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0 cSummation1 = cP11 and cP12 and cP13 if cSummation1 then backgroundcolor("green",30) endif return cP11, cP12*2, cP13*3, cSummation1*4 style(line,2)

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  P1=5 MyEMA1 = ExponentialAverage[5](close) MyEMA2 = ExponentialAverage[10](close) MyEMA3 = ExponentialAverage[20](close) MyEMA4 = ExponentialAverage[50](close)   Cross1 = MyEMA1 crosses over MyEMA2 Cross2 = MyEMA1 crosses over MyEMA3 Cross3 = MyEMA1 crosses over MyEMA4   cP11 = summation[P1](Cross1) > 0 cP12 = summation[P1](Cross2) > 0 cP13 = summation[P1](Cross3) > 0   cSummation1 = cP11 and cP12 and cP13   if cSummation1 then    backgroundcolor("green",30) endif   return cP11, cP12*2, cP13*3, cSummation1*4 style(line,2)

  

  Iván

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  01/13/2026 at 2:23 PM #255259
  thomas2004ch

  Sorry, maybe I made some error anywhere in my code. I rewrote my code and it works now.

  @Iván:

  The ticker is the Alamos Gold (AGI). You can test it during the August 2025.

  1 user thanked author for this post.

  Iván

  

  thomas2004ch

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