A coding question

• 07/10/2022 at 10:44 AM #197072
  WingYip

  Hi, it would be nice if someone can answer this….

  Are this 2 code are the same and work the same way?

  CLOSE < low[1] or CLOSE < low[2] or CLOSE < low[3] or CLOSE < low[4]

  ——————————————–

  CLOSE < (low[1] or low[2] or low[3] or low[4])

  Many thanks

  

  WingYip

  Participant

  Topics: 5

  Replies: 24

  Been thanked: 4 times
  07/10/2022 at 11:16 AM #197073
  WingYip

  Hi, it would be nice if someone can answer this….

  Are this 3 code are the same and work the same way?

  CLOSE < low[1] or CLOSE < low[2] or CLOSE < low[3] or CLOSE < low[4]

  ——————————————–

  CLOSE < (low[1] or low[2] or low[3] or low[4])

  ————————————————-

  c1 = CLOSE < low[1]

  c2 = CLOSE < low[2]

  c3 = CLOSE < low[3]

  c4 = CLOSE < low[4]

  s1 = c1 or C2 or C3 or c4

  Many thanks

   

  

  WingYip

  Participant

  Topics: 5

  Replies: 24

  Been thanked: 4 times
  07/10/2022 at 12:31 PM #197074
  GraHal

  If you number your options then it’s easier fior us to help you as we can easily refer to numbers. 🙂

  This

  S1 = CLOSE < low[1] or CLOSE < low[2] or CLOSE < low[3] or CLOSE < low[4]

  is same as

  c1 = CLOSE < low[1]

  c2 = CLOSE < low[2]

  c3 = CLOSE < low[3]

  c4 = CLOSE < low[4]

  s1 = c1 or C2 or C3 or c4

   

  This one

  CLOSE < (low[1] or low[2] or low[3] or low[4])

  won’t work for what you want it to do, e.g. or  low[2]  will only give you the value of low 2 bars ago.

  1 user thanked author for this post.

  Midlanddave

  

  GraHal

  Participant

  Topics: 220

  Replies: 9002

  Been thanked: 2293 times
  07/10/2022 at 12:39 PM #197075
  JS

  Code1,2,and 3

  Code1 = Close<Low[1] or Close<Low[2] or Close<Low[3] or Close<Low[4] Code2 = Close<Low[1] or Low[2] or Low[3] or Low[4] c1 = Close<Low[1] c2 = Close<Low[2] c3 = Close<Low[3] c4 = Close<Low[4] Code3 = c1 or c2 or c3 or c4 Return Code1 as "Code1", Code2 as "Code2", Code3 as "Code3"

  1 2 3 4 5 6 7 8 9 10 11

  Code1 = Close<Low[1] or Close<Low[2] or Close<Low[3] or Close<Low[4] Code2 = Close<Low[1] or Low[2] or Low[3] or Low[4]   c1 = Close<Low[1] c2 = Close<Low[2] c3 = Close<Low[3] c4 = Close<Low[4]   Code3 = c1 or c2 or c3 or c4   Return Code1 as "Code1", Code2 as "Code2", Code3 as "Code3"

  In addition to GraHal’s explanation:

  You can set up a simple indicator to test…

  Then you see that Code1 and Code3 give the same results (0 or 1) but that Code2 is always true (always 1). This is probably because in Code2 you don’t give a condition to Low[2], Low[3] and Low[4]. So you’re basically saying here, is there a Low[2] or a Low[3] or a Low[4] (and there always are).

  2 users thanked author for this post.

  Midlanddave, GraHal

  

  JS

  Participant

  Topics: 27

  Replies: 2038

  Been thanked: 1086 times
  07/10/2022 at 2:26 PM #197077
  robertogozzi

  As to your first post:

  • the first line is correct, it’ll be true whenever CLOSE < anyone of the previous 4 LOWs
  • the second line is logically incorrect, as it will ALWAYS be true, as you do not compare CLOSE to those LOWS; you compare CLOSE to the fact that anyone of those LOWs is <> 0, which cannot be false.

   

  

  robertogozzi

  Moderator

  Topics: 69

  Replies: 17524

  Been thanked: 4278 times
  07/10/2022 at 3:31 PM #197082
  WingYip

  thank you guys, got it now, very appreciate 🙂

  

  WingYip

  Participant

  Topics: 5

  Replies: 24

  Been thanked: 4 times
• Author
  Posts