Wilderaverage syntax errors need correct syntax format.

• 07/07/2020 at 2:37 PM #138643
  Philstrading

  Hi, well I’m sure its obvious to someone, but when I try to put in the syntax for a wilderaverage the help is of no help. I want the syntax for wilderaverage 4 periods, horizontal shift -1. vertical shift 0 applied to close

  No matter how I write it, parenthesis, brackets, commas. I can’t seem to put it in without syntax errors, yet the help states you can spcify them , just doesnt tell you the correct syntax.

  A simple thing, but I must be missing something.

  Anyone spell this out for me? Be appreciated.

  Thanks

  

  Philstrading

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  07/07/2020 at 2:47 PM #138644
  Nicolas

  Horizontal shift is just a way to get the current value moved visually on the right or the left , so what do you expect exactly?

  

  Nicolas

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  07/07/2020 at 3:00 PM #138648
  Philstrading

  LOL.. 🙂 hmmm, ok, clearly not thinking about it too deeply here…. that being the case its not of much value… I’ll mess about a bit more… Twas looking at crosses that may be of some value scalping. Wanted that variance in current time of course. I’ll mess about with programming perhaps..

  Cheers Robert.

  

  Philstrading

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  07/08/2020 at 7:26 AM #138695
  Nicolas

  Get the Xth previous value of a variable:

  x = 5 //period offset var = wilderaverage[20](close) varX = var[x] return varX

  1 2 3 4 5

  x = 5 //period offset var = wilderaverage[20](close) varX = var[x]   return varX

   

  

  Nicolas

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  07/08/2020 at 11:40 AM #138729
  Philstrading

  Ok cheers Nicolas. I will take a mosey at that.

  

  Philstrading

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