Sell at market when X%-profit

• 10/28/2022 at 12:45 PM #203146
  SnorreDK

  Is this possible within a candle. Dont wait untill candleclose

  if X% in profit and Bear1 then sell at market Endif

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  if X% in profit and Bear1 then sell at market Endif

  This code is not what i need, though it waitns untill candleclose:

  if longonmarket and bear1 and (close > positionprice * 1.01) then SELL AT MARKET endif

  1 2 3

  if longonmarket and bear1 and (close > positionprice * 1.01) then SELL AT MARKET endif

   

   

   

  

  SnorreDK

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  10/28/2022 at 1:47 PM #203150
  JS

  If LongOnMarket and Bear1 and Close > PositionPrice * 1.01 then
  Sell at (PositionPrice * 1.01) Stop
  EndIf

  

  JS

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  10/28/2022 at 1:49 PM #203151
  SnorreDK

  Thanks JS, but does this mean I have to wait for the candleclose?

  

  SnorreDK

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  10/28/2022 at 1:56 PM #203152
  JS

  No, you don’t have to wait because it’s a STOP order…

  

  JS

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  10/29/2022 at 4:10 PM #203194
  SnorreDK

  If I do understand You correct then A=1 and A=2 would give the same result but it does not.

  if A=1 then posProfit = (((close - positionprice) * pointvalue) * countofposition) / pipsize IF LONGONMARKET AND (posProfit > 0) and Bear1 THEN SELL AT MARKET ENDIF endif if A=2 then IF LONGONMARKET AND Bear1 THEN SELL at (positionprice*1) stop ENDIF endif

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  if A=1 then posProfit = (((close - positionprice) * pointvalue) * countofposition) / pipsize IF LONGONMARKET AND (posProfit > 0) and Bear1 THEN SELL AT MARKET ENDIF endif if A=2 then IF LONGONMARKET AND Bear1 THEN SELL at (positionprice*1) stop ENDIF endif

   

  

  SnorreDK

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  10/29/2022 at 4:39 PM #203195
  JS

  Hi @SnorreDK

  You can’t compare them because a “Market” order always gives a different result than a “Stop” order…

  If A=2 then

  IF LONGONMARKET AND Bear1 and Close > (PostionPrice * 1.01) THEN

  SELL at (PositionPrice * 1.01) stop

  EndIf

  EndIf

  

  JS

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