Price Time and MA Screener

thesage · 2021-06-18T09:46:24+00:00

Hi, I’m new here and am in need of some help for a screener I am trying to build. My coding knowledge isn’t great and I’ve been trying to sort of fudge together code from what I’ve been able to find here on the forums but to not much success. As a run down what I am trying to achieve is the following:- 50ema above 200ema 50ema above 200ema for at least 40 days price below 20ema and/or price has dropped EMA200) SCREENER[Condition] Thank you in advance for any help

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06/18/2021 at 10:46 AM #171973 quote
thesage
Participant

New
Hi,

I’m new here and am in need of some help for a screener I am trying to build. My coding knowledge isn’t great and I’ve been trying to sort of fudge together code from what I’ve been able to find here on the forums but to not much success.

As a run down what I am trying to achieve is the following:-

50ema above 200ema

50ema above 200ema for at least 40 days

price below 20ema and/or price has dropped <=10% in the last 10 days

For the code so far I’ve got the below to return stocks where the 50ema is above the 200ema.
```
timeframe(Daily)
 
EMA50 = ExponentialAverage[50] (close)
EMA200 = ExponentialAverage[200] (close)
 
Condition = (EMA50 > EMA200)
 
SCREENER[Condition]
```
Thank you in advance for any help
06/18/2021 at 11:36 AM #171979 quote
robertogozzi
Moderator

Legend
There you go:
```
timeframe(Daily)
EMA20  = ExponentialAverage[20] (close) 
EMA50  = ExponentialAverage[50] (close)
EMA200 = ExponentialAverage[200] (close)
c1     = (summation[40](EMA50 > EMA200) = 40) //Ema50 > Ema200 for at least 40 days (the current one is included)
c2     = close < Ema20
c3     = (close / close[10]) <= 0.90          //price dropped at least 10% in the last 10 days
Condition = c1 AND (c2 OR c3)
SCREENER[Condition]
```
thesage thanked this post
06/18/2021 at 1:04 PM #171988 quote

thesage
Participant

New

Thanks for the quick reply and code. I really appreciate that 🙂

What I’ll do as well is try and go through the code to learn for future reference what each of the bits means and does.
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