Finding the High of a series of bars

• 09/26/2025 at 6:25 AM #251834
  Mellstock

  How do. I find the High of a series of bars.

  say countofpostions = 10

  How can I find the Maximum (or highest) of the High of the bar when countofpositions became 10 and the High of the current bar (and subsequent bar when that happens).

  Thank you

  

  Mellstock

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  09/26/2025 at 8:40 AM #251836
  Iván

  You can use the HIGHEST function in ProBuilder to find the maximum of the last N bars.
  In your case, if you want to get the highest value of the High over the last 10 bars, you can do it like this:

  countofpositions = 10 maxHigh = HIGHEST[countofpositions](High) if maxHigh = high then DRAWTEXT("MaxHigh = #maxHigh#", BarIndex, High) endif return maxHigh

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  countofpositions = 10 maxHigh = HIGHEST[countofpositions](High)   if maxHigh = high then DRAWTEXT("MaxHigh = #maxHigh#", BarIndex, High) endif   return maxHigh

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  JC_Bywan

  

  Iván

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  09/26/2025 at 10:18 AM #251842
  JC_Bywan

  Hi,

  the request is slightly ambiguous because you don’t use the same spelling for countofposition as an existing proorder keyword, so it might give the impression you meant it as a variable for the series length, but it could be you really meant “when my position reaches size 10”:

  https://www.prorealcode.com/documentation/countofposition/

  so, assuming the latter and using countofposition as the above proorder command counting your number of contracts/shares (so spelling with no “s”, and adding the missing “i”) rather than a personal variable, then you could try this to find highest value of both highs, regardless of how long it took between reaching size 10 and current bar (NB: this piece of code doesn’t extrapolate on your behalf what value to give to “myhighest” after countofposition is not 10 anymore):

  if countofposition[1]<countofposition AND countofposition=10 then highwhen10=high elsif countofposition<>10 then highwhen10=0 endif if countofposition=10 then myhighest= max(highwhen10,high) endif

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  if countofposition[1]<countofposition AND countofposition=10 then highwhen10=high elsif countofposition<>10 then highwhen10=0 endif   if countofposition=10 then myhighest= max(highwhen10,high) endif

   

   

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  Iván

  

  JC_Bywan

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  09/29/2025 at 11:55 AM #251932
  Mellstock

  Thanks for replies. The situation is for when countposition equals a certain number.

  Does TradeIndex(1) help here.

  Would

  If Countposition = 10 Then
  MaxH = Highest[TradeIndex(1)-Barindex +1]

  Endif

  work?

  Thank You

   

  

  Mellstock

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  09/29/2025 at 8:18 PM #252009
  robertogozzi

  Maybe this one?

  When10bar = 0 When10Hi = 0 NextBar = 0 NextHi = 0 CurrentBar = 0 CurrentHi = high myPos = CountOfPosition FOR i = 0 TO BarIndex - 1 IF myPos[i] = 10 THEN When10bar = i When10Hi = high[i] NextBar = i - 1 NextHi = high[NextBar] break ENDIF ENDIF NEXT graph When10bar graph When10Hi graph NextBar graph NextHi graph CurrentBar graph CurrentHi

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  When10bar  = 0 When10Hi   = 0 NextBar    = 0 NextHi     = 0 CurrentBar = 0 CurrentHi  = high myPos      = CountOfPosition FOR i = 0 TO BarIndex - 1    IF myPos[i]  = 10 THEN       When10bar = i       When10Hi  = high[i]       NextBar   = i - 1       NextHi    = high[NextBar]       break    ENDIF ENDIF NEXT graph When10bar graph When10Hi graph NextBar graph NextHi graph CurrentBar graph CurrentHi

   

   

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  robertogozzi

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  10/02/2025 at 6:52 AM #252087
  Mellstock

  I am still trying to get this issue straight.

  Would this work?

  If Abs(countofposition) = 10 Then

  TopLevel = Highest[BarIndex-TradeIndex+1]

  Endif

  

  Mellstock

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  10/02/2025 at 10:31 AM #252093
  robertogozzi

  Yes, that seems correct.

  You can easily check it by GRAPHing TopLevel to verify if it’s the correct value when the last entry occurred:

  GRAPH TopLevel //or GRAPHONPRICE TopLevel

  1	GRAPH TopLevel //or GRAPHONPRICE TopLevel

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  Mellstock

  

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