Conversione funzione matematica Cube Root

• 09/04/2019 at 3:21 PM #106501
  coscar

  Salve

  avrei bisogno di un aiuto, devo codificare un indicatore che utilizza la seguente formula:

  Cube root

  x, cubert

  y=x^(1/3)

   

  dove x = Close[1]

  Potreste aiutarmi a convertrla?

  grazie in anticipo.

  Buon lavoro-

  

  coscar

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  09/04/2019 at 3:25 PM #106502
  Nicolas

  Il calcolo EXP non è disponibile come istruzione nella lingua. Ma potremmo usare questo tipo di formula invece:

  y = x^p = e^(p*LN(x))

  1	y = x^p = e^(p*LN(x))

  Questo potrebbe quindi essere codificato come:

  y = EXP (p * LOG (x))

  1	y = EXP (p * LOG (x))

  Funziona benissimo.

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  coscar

  

  Nicolas

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  09/04/2019 at 3:42 PM #106509
  coscar

  Grazie Nicolas

  potresti verificare se è giusto?

  Cubert

  Input1 = Close[1] Input2 = Open Input3 = Average [5](close) Input4 = Average [10] (close) Input5 = Average [20] (close) CloseCubert = EXP (1/3 * LOG (Input1)) OpenCubert = EXP (1/3 * LOG (Input2)) Media5Cubert = EXP (1/3 * LOG (Input3)) Media10Cubert = EXP (1/3 * LOG (Input4)) Media20Cubert = EXP (1/3 * LOG (Input5)) return CloseCubert,OpenCubert,Media5Cubert,Media10Cubert,Media20Cubert

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  Input1 = Close[1] Input2 = Open Input3 = Average [5](close) Input4 = Average [10] (close) Input5 = Average [20] (close)   CloseCubert = EXP (1/3 * LOG (Input1)) OpenCubert  = EXP (1/3 * LOG (Input2)) Media5Cubert = EXP (1/3 * LOG (Input3)) Media10Cubert = EXP (1/3 * LOG (Input4)) Media20Cubert = EXP (1/3 * LOG (Input5)) return CloseCubert,OpenCubert,Media5Cubert,Media10Cubert,Media20Cubert

   

  

  coscar

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  09/04/2019 at 3:49 PM #106510
  coscar

  Scusatemi ma non riesco a valorizzare il paramentro Y1 , potreste aiutarmi nella codifica?

  grazie

  Close-1 = X^(1/3) di Close[1] Media5g = X^(1/3) di Average [5](close) Media10g = X^(1/3) di Average [10](close) Media20g = X^(1/3) di Average [20](close) Media50g = X^(1/3) di Average [50](close) N127 = -1.13611 - media20g*0.284623 + media20g*N244*0.348839 - media20g^2*0.083844 + N244*3.25716 - N244^2*1.11986 N244 = 1.0421 - Media5g*(Close-1)*0.340898 + Media5g^2*0.338756 - (Close-1)*0.808886 + (Close-1)^2*0.785873 N126 = -0.772251 - N239*N260*46.7862 + N239^2*23.6232 + N260*2.34161 + N260^2*22.581 N260 = 1.04843 + Media5g*Media10g*1.20493 + Media5g^2*0.00866418 - Media10g*0.81701 - Media10g^2*0.427549 N239 = 1.04261 - Media50g*0.0912637 + Media50g*(Close-1)*0.0915926 - (Close-1)*0.700646 + (Close-1)^2*0.677317 Y1 = -0.121345 + N126*1.20688 - N126*N127*260.841 + N126^2*130.314 + N127^2*130.439

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  Close-1 = X^(1/3) di Close[1] Media5g = X^(1/3) di Average [5](close) Media10g = X^(1/3) di Average [10](close) Media20g = X^(1/3) di Average [20](close) Media50g = X^(1/3) di Average [50](close)   N127 = -1.13611 - media20g*0.284623 + media20g*N244*0.348839 - media20g^2*0.083844 + N244*3.25716 - N244^2*1.11986 N244 = 1.0421 - Media5g*(Close-1)*0.340898 + Media5g^2*0.338756 - (Close-1)*0.808886 + (Close-1)^2*0.785873 N126 = -0.772251 - N239*N260*46.7862 + N239^2*23.6232 + N260*2.34161 + N260^2*22.581 N260 = 1.04843 + Media5g*Media10g*1.20493 + Media5g^2*0.00866418 - Media10g*0.81701 - Media10g^2*0.427549 N239 = 1.04261 - Media50g*0.0912637 + Media50g*(Close-1)*0.0915926 - (Close-1)*0.700646 + (Close-1)^2*0.677317   Y1 = -0.121345 + N126*1.20688 - N126*N127*260.841 + N126^2*130.314 + N127^2*130.439

   

  

  coscar

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  09/05/2019 at 8:35 AM #106550
  Nicolas

  Scusa ma non capisco di cosa hai bisogno? Potresti eventualmente pubblicare l’intero codice che desideri creare, in questo caso potrei avere un quadro perfetto di ciò che deve essere fatto ..

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  coscar

  

  Nicolas

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