coding 4-day low/high

• 04/13/2019 at 4:56 PM #96361
  therookie

  I am wondering how to put down two things in code:

  1: Go short if today’s close is a new 4-day high

  2. Close the short position if today’s close is a new 4-day low

  Help would be much appreciated!

  

  therookie

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  04/13/2019 at 5:41 PM #96362
  Harrys

  DEFPARAM PRELOADBARS = 100 DEFPARAM Cumulateorders = False s1 = (close = highest[4](close)) exit1 = (close = lowest[4](close)) size = 1 If s1 THEN sellshort size contracts at market ENDIF If exit1 and shortonmarket then exitshort at market ENDIF

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

  DEFPARAM PRELOADBARS = 100 DEFPARAM Cumulateorders = False   s1 = (close = highest[4](close)) exit1 = (close = lowest[4](close))   size = 1   If s1 THEN sellshort size contracts at market ENDIF   If exit1 and shortonmarket then exitshort at market ENDIF

  Hope this should help

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  therookie

  

  Harrys

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  04/13/2019 at 5:54 PM #96364
  Vonasi

  therookie wrote:

  Go short if today’s close is a new 4-day high

  Bit difficult to be 100% certain what you mean by this. Do you mean that today’s close has to be higher than the last three closes (which is what Harrys has coded) or do you mean that today’s close has to be higher than the highest high of the last three candles?

  For the latter your conditions would need to be:

  s1 = close > highest[3](high[1]) exit1 = close < lowest[3](low[1])

  1 2	s1 = close > highest[3](high[1]) exit1 = close < lowest[3](low[1])

   

  

  Vonasi

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  04/14/2019 at 12:20 PM #96386
  therookie

  Ok good question, maybe I didn’t specify it well enough.

  I want today’s close to be higher than the last 3 days’ closes so I guess Harrys code is what I want.

  But why is there equal signs and not ‘<‘ and ‘>’ signs?

  

  therookie

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  04/14/2019 at 12:39 PM #96390
  Nicolas

  Try this version: 😉

  s1 = close > highest[3](close[1]) exit1 = close < lowest[3](close[1])

  1 2	s1 = close > highest[3](close[1]) exit1 = close < lowest[3](close[1])

  s1 = close is higher than the higher close of the last 3 days

  exit1 = close is lower than the lower close of the last 3 days

  

  Nicolas

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  04/14/2019 at 12:44 PM #96391
  robertogozzi

  Harry’s code (lines 4-5) does its job correctly, current close MUST be >= than the previous 3 candles.

  Vonasi’s code does the same job with a slightly different approach.

  

  robertogozzi

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  04/14/2019 at 12:50 PM #96393
  robertogozzi

  I can’t edit from my mobile.

  Vonasi’s code does something different.

  Nicolas’code has just a slightly different approach.

  

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  04/14/2019 at 2:29 PM #96405
  Vonasi

  Harrys code does the job by obtaining the value of the highest close in the last four candles and comparing it to the current close. It assumes that if they are the same value then this close must be the highest. It does not however allow for the fact that one or more of the closes could have identical values in which case your entry criteria is not strictly being met. Nicolas’ version and my version do allow for this possibility. Nicolas’ does it with the last three closes which is what you want whereas my version just does the same thing with the last three highs.

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  Vonasi

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  04/14/2019 at 3:31 PM #96407
  therookie

  Thank you guys for the help and you Vonasi for the explanation.

  

  therookie

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