Close at a set time on a previous day 

• 05/27/2020 at 9:55 PM #133512
  Bolt

  Can some one please point me in the correct direction for some code, I am aiming for the following:

  Close at a set time on a previous day

  Where the time and the relative day are variable.

  Many thanks

  

  Bolt

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  05/27/2020 at 11:46 PM #133524
  robertogozzi

  How can you close at a set time on a previous day, say yesterday?

  You should have closed yesterday.

  

  robertogozzi

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  05/29/2020 at 4:44 PM #133798
  Bolt

  Apologies I might not have been clear in my wording. I am trying to perform a price test on historic prices as a set time of day to base the decision to open on.

  In words I am trying to achieve the following:

  I want the price at 4pm 5 days ago to compare to the price at 4pm yesterday. If this is positive I will open a position at the today at 11am .

  I have tried the below but is it not working as expected on 1 hour charts

  IF (dclose (5) <= dclose(1)) AND (hour=16 and minute = 0000) THEN

  C1= 1

  endif

  IF (C1=1 AND time = 080000 AND not daysForbiddenEntry) THEN

  BUY 1 PERPOINT AT MARKET

  ENDIF

   

  I am sure it must be simple, just new to this and trying to get some basic testing done.

  Man thanks for any input in advance.

   

   

  

  Bolt

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  05/29/2020 at 5:31 PM #133800
  robertogozzi

  I understand. It’s not possible to reference past times using brackets as only past bars can be referenced.

  You have to save 5 prices at the same time, shifting them as days go by, then compare each day the previous one with the 5th previous one. You’ll have to use 5 different variable names (v11 might allow using arrays, but they are not much help this time):

  ONCE Day5 = 999999 ONCE Day4 = 999999 ONCE Day3 = 999999 ONCE Day2 = 999999 ONCE Day1 = 999999 IF time = 160000 THEN Day5 = Day4 Day4 = Day3 Day3 = Day2 Day2 = Day1 Day1 = close ENDIF IF time = 110000 THEN C1 = 0 IF Day5 <= Day1 THEN C1 = 1 ENDIF endif IF (C1=1 AND time = 110000 AND not daysForbiddenEntry) THEN BUY 1 PERPOINT AT MARKET ENDIF

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

  ONCE Day5 = 999999 ONCE Day4 = 999999 ONCE Day3 = 999999 ONCE Day2 = 999999 ONCE Day1 = 999999 IF time = 160000 THEN    Day5 = Day4    Day4 = Day3    Day3 = Day2    Day2 = Day1    Day1 = close ENDIF IF time = 110000 THEN    C1 = 0    IF Day5 <= Day1 THEN       C1 = 1    ENDIF endif IF (C1=1 AND time = 110000 AND not daysForbiddenEntry) THEN    BUY 1 PERPOINT AT MARKET ENDIF

   

   

  

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  05/29/2020 at 5:34 PM #133801
  robertogozzi

  Sorry, I just edited line 15 due to mistyping.

  

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