Can I set a flag wich stays over a number of bars

• 06/01/2022 at 6:30 AM #194366
  pdrh

  LFlag=0 ignored, indicator1 = CALL "HARKO_Fractals BW"[5](close) c1=close crosses over indicator1 If c1 then LFlag=1 Entry=indicator1 ENDIF c2=low<Entry IF c2 AND LFlag=1 AND LT<1 And timeEnterBefore AND timeEnterAfter THEN BUY 1 CONTRACT AT Entry Limit LT=LT+1 ENDIF

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  LFlag=0 ignored, indicator1 = CALL "HARKO_Fractals BW"[5](close) c1=close crosses over indicator1 If c1 then LFlag=1 Entry=indicator1 ENDIF c2=low<Entry IF c2 AND LFlag=1 AND   LT<1 And timeEnterBefore AND timeEnterAfter THEN BUY 1 CONTRACT AT Entry Limit LT=LT+1 ENDIF

  I am wanting to set a flag that stays for a number of bars .

  With the code above , the flag resets to zero after the bar that triggered it so that I cannot get a limit entry .

  

  pdrh

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  06/01/2022 at 8:20 AM #194379
  PeterSt

  Hi pdrh – The base of the solution you ask for is chaning the first line into

  Once LFlag=0

  1	Once LFlag=0

  Now its value will stay because only at the first call of your code it is set to 0.

  This is not the complete solution, because somewhere you will need to reset it. This will come down to

  If OnMarket then LFlag = 0 endif

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  If OnMarket then   LFlag = 0 endif

  I think this is still not correct, because you’d want to set FLag each new call, which could be done like this :

  LFlag=close crosses over indicator1

  1	LFlag=close crosses over indicator1

  Of course you’d need to adjust the remainder somewhat. This is not easy to see because it depends on what you want. For example, letting LFlag be on lways after this crssing happened once, does not seem the correct solution to me. This would rather be to reset LFlag at each call … but … (this is what the last by me shown line does and which makes the first line’s adjustment redundant).

  2 users thanked author for this post.

  pdrh, Nicolas

  

  PeterSt

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