calculating the etality of the Bollinger band

• 07/16/2025 at 7:35 PM #248901
  juld63

  Hi everyone, I want to be able to determine whether the lower BB at [0] is either:

  • going up from lower than close/10000 and reaching a local max at [0];
  • going down from a local max (itself defined by having come up from a preceding low lower than close/10000 relative to that local max)  but not too much (less than close/500);
  • going down from a local max   by more  than close/500.

  I’ve tried to write it that way bbut it always gives 0 as a result. Even if I pu in the FOR loop a condition that is always verified e.g. b=b it still gives me 0. Any idea what is missing ? Thanks !

  PN= close/10000 //bollinger a = Average[200](Close) // On définit l'écart-type StdDeviation = STD[200](Close) Bsup2 = a + 2 * StdDeviation Binf2 = a - 2 * StdDeviation Bsup15 = a + 1.5 * StdDeviation Binf15 = a - 1.5 * StdDeviation etalite=0 FOR b=1 to b=500 DO IF (Highest[b](Binf15)-Binf15[0]>=PN AND Highest[b](Binf15)-Binf15[b]<PN) OR (Highest[b](Binf15)-Binf15[0]<PN AND Binf15[0]-Binf15[b]<PN) THEN continue ELSIF (Highest[b](Binf15)-Binf15[b]>=PN AND Highest[b](Binf15)-Binf15[0]<20*PN) OR (Highest[b](Binf15)=Binf15[0] AND Binf15[0]-Binf15[b]>=PN) THEN etalite=1 break ELSIF Highest[b](Binf15)-Binf15[b]>=PN AND Highest[b](Binf15)-Binf15[0]>=20*PN THEN etalite=0 break ENDIF NEXT RETURN etalite

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

  PN= close/10000 //bollinger a = Average[200](Close) // On définit l'écart-type StdDeviation = STD[200](Close) Bsup2 = a + 2 * StdDeviation Binf2 = a - 2 * StdDeviation Bsup15 = a + 1.5 * StdDeviation Binf15 = a - 1.5 * StdDeviation   etalite=0 FOR b=1 to b=500 DO IF (Highest[b](Binf15)-Binf15[0]>=PN AND Highest[b](Binf15)-Binf15[b]<PN) OR (Highest[b](Binf15)-Binf15[0]<PN AND Binf15[0]-Binf15[b]<PN) THEN continue ELSIF (Highest[b](Binf15)-Binf15[b]>=PN AND Highest[b](Binf15)-Binf15[0]<20*PN) OR (Highest[b](Binf15)=Binf15[0] AND Binf15[0]-Binf15[b]>=PN) THEN etalite=1 break ELSIF Highest[b](Binf15)-Binf15[b]>=PN AND Highest[b](Binf15)-Binf15[0]>=20*PN THEN etalite=0 break ENDIF NEXT   RETURN etalite

   

  

  juld63

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  07/17/2025 at 12:06 PM #248931
  robertogozzi

  Line 12 should read:

  FOR b=1 to 500 DO

  1	FOR b=1 to 500 DO

  as it is now, its meaning is a boolean comparison, because it will check if b=500, which is always false because it starts from 1 which is different from 500, unless it’s the very last iteration to which it seems to never arrive as it always breaks earlier.

  As to the rest of the code I can’t exactly understand what you want to do.

   

   

   

   

   

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  robertogozzi

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  07/17/2025 at 12:09 PM #248932
  juld63

  Thanks, I realized just 10 minutes ago that this was the mistake! I new it had to be something super basic because nothing worked. Good catch!

  

  juld63

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