apply my personnal indicator to graph

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01/22/2019 at 9:14 PM #89371 quote
Vonasi
Moderator

Master
```
multiple = 1 //(or any value you choose to tune the indicator to the market)
x = 0 -(????) //( ???? = output of your indicator usually between -15 and + 15)
z = medianprice * (1 + (x / 100) * multiple)
return z
```
If your indicator output is normally between -15 and +15 then the above will do what I was suggesting. Tune the multiple to match individual markets.
01/23/2019 at 9:35 AM #89399 quote

Nicolas
Keymaster

Master

Porion wrote:

i can still use it only as support/resistance when it crosses zero but i wanted to improve it a little bit more.

oh, easier to understand with a picture! Indeed, what you want is possible. Please share the indicator code in order to incorporate all the necessary code to it. I’m sure we’ll be able to add the graphical component you miss.

01/23/2019 at 1:39 PM #89432 quote
Porion
Participant

New
```
a = RSI[30](close) - RSI[100](close)
```
it’s a really simple code, but it can give you pretty decent signal if you use it correctly.
01/23/2019 at 3:32 PM #89458 quote
Vonasi
Moderator

Master
Porion wrote:

a = RSI[30](close) – RSI[100](close)

That is a bounded indicator as RSI is bounded between 0 and 100 so your combination of two RSI’s is now bounded between 100 and -100 as those are the maximum and minimum results possible.

If you apply your indicator to my code you get a line that flips above and below price.
```
multiple = 1 
x = 0 - (RSI[30](close) - RSI[100](close))
z = medianprice * (1 + (x / 100) * multiple)
return z
```
[attachment file=89459]

robertogozzi and Nicolas thanked this post

Screenshot_4.png
01/23/2019 at 3:43 PM #89461 quote
robertogozzi
Moderator

Master
Nice job Vonasi, but line 3 should be replaced by
```
z = medianprice * (1 - (x / 100) * multiple)
```
to replicate the true indicator.
01/23/2019 at 3:53 PM #89463 quote

Vonasi
Moderator

Master

Porion wrote:

when my indicator turn positive, it should be below the price and vice versa.

I think mine is correct if I understood the above comment from the OP correctly.

01/23/2019 at 4:06 PM #89465 quote
Vonasi
Moderator

Master
Here is a version that draws a buy or sell arrow when the line crosses medianprice as Porion requested this originally I seem to recall.
```
multiple = 1
x = 0 - (RSI[30](close) - RSI[100](close))
z = medianprice * (1 + (x / 100) * multiple)

if z crosses over medianprice then
drawarrowdown(Barindex, medianprice + range) coloured(128,0,0)
endif

if z crosses under medianprice then
drawarrowup(Barindex, medianprice - range) coloured(0,128,0)
endif

return z
```
01/23/2019 at 4:55 PM #89472 quote

Porion
Participant

New

Thanks a lot guys for your help, it seems quite encouraging. i used Vonasi’s first code. i think it would be better if i was able to smooth it a little bit but it return me an error message.

aaa-2.png

01/23/2019 at 5:09 PM #89475 quote

Porion
Participant

New

Quite interessing as i’m now able to see where i should short (late december, as you can see on the chart) but with the old indicator i wasn’t.

aaa-3.png

01/23/2019 at 6:38 PM #89478 quote
Vonasi
Moderator

Master
Porion wrote:

i think it would be better if i was able to smooth it a little bit

Try changing line for something like this:
```
x = exponentialaverage[3](0 - (RSI[30](close) - RSI[100](close)))
```
01/23/2019 at 6:44 PM #89479 quote

Vonasi
Moderator

Master

I think I messed up the code in post #89465 as I was playing with Roberto’s suggestion. I have edited the post and corrected it now so you might want to try it again.

01/23/2019 at 7:47 PM #89489 quote
Porion
Participant

New
Thanks Vonasi,

i added
```
a1 = ((highest[3](z))+(lowest[3](z)))/2
```
to your code to smooth the indicator a little bit(in yellow)

aaa-4.png
01/23/2019 at 8:05 PM #89494 quote

Vonasi
Moderator

Master

Increasing the period from 3 upwards will smooth it more but at the expense of lag.
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