Using a time loop to find High or Low during defined period

• 08/01/2017 at 8:34 AM #42158
  nickp104

  I would like to find out how to find a high or low within a defined area.  To test, I used the example code below but probuilder tells me there’s a syntax error in line 14 – there are only 13 lines of code.

  Find the high between bars 20 and 45

  FOR i = 20 TO 45 DO P1High = high c1 = CLOSE > P1High IF C1 THEN BUY 1 SHARES AT MARKET ENDIF

  1 2 3 4 5 6 7 8 9 10

  FOR i = 20 TO 45 DO P1High = high     c1 = CLOSE > P1High     IF C1 THEN BUY 1 SHARES AT MARKET ENDIF

  It would be great if someone could let me know what I’m missing or point me towards code that would allow me to do this…

  

  nickp104

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  08/01/2017 at 9:09 AM #42161
  Nicolas

  A FOR/NEXT loop is always made with 3 keywords: FOR + DO + NEXT

  The correct syntax should be:

  hh = 0 FOR i = 20 TO 45 DO hh = max(hh,high[i]) NEXT c1 = CLOSE > hh IF C1 THEN BUY 1 SHARES AT MARKET ENDIF

  1 2 3 4 5 6 7 8 9 10 11

  hh = 0   FOR i = 20 TO 45 DO hh = max(hh,high[i]) NEXT   c1 = CLOSE > hh   IF C1 THEN BUY 1 SHARES AT MARKET ENDIF

  But you don’t have to do a loop to find the highest high of 20 bars ago, you could also use this instruction:

  hh = highest[25](high)[20]

  1	hh = highest[25](high)[20]

  it will find for you, the value of the highest high 25 periods but 20 bars ago.

  

  Nicolas

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  08/01/2017 at 10:07 AM #42167
  juanj

  @Nicolas I have always used the formula you referenced to but at some point realized that for some unknown reason it doesn’t give the same result as a loop. For example:

  PSH = Highest[10](high)[1] //Previous Swing High PSL = Lowest[10](low)[1] //Previous Swing Low

  1 2	PSH = Highest[10](high)[1] //Previous Swing High PSL = Lowest[10](low)[1] //Previous Swing Low

  Should yield the same result as:

  PSH = high[1] //Previous Swing High PSL = low[1] //Previous Swing Low For i = 2 to 10 Do If high[i] > PSH Then PSH = high[i] ElsIf low[i] < PSL Then PSL = low[i] EndIf Next

  1 2 3 4 5 6 7 8 9

  PSH = high[1] //Previous Swing High PSL = low[1] //Previous Swing Low For i = 2 to 10 Do If high[i] > PSH Then PSH = high[i] ElsIf low[i] < PSL Then PSL = low[i] EndIf Next

  And unless I am mistaken it doesn’t?

  

  juanj

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  08/01/2017 at 11:02 AM #42182
  Nicolas

  @juanj

  Because you are using “elsif”, you should make 2 different conditional statement IF/ENDIF, one for highest high and one for lowest low.

  

  Nicolas

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  08/02/2017 at 7:02 AM #42282
  nickp104

  Thank you all for your excellent advice … problem solved.

  

  nickp104

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