Multiple Line IF Statement

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05/22/2025 at 11:14 AM #247480 quote

MacroT
Participant

Average

I have a multiple line if statement used to filter out a series of constraints. I would like to know if there is a function to exit the if statement if a condition is met without running through the whole statement.

Eg

IF Condition A then

X = 0

ELSIF Condition B then

X = 1

ELSIF Condition C then

X = 0

ELSE

X=1

ENDIF

In the example above assume there is an overlap between Condition A and B.

If the code runs on this overlap, then X is set to 0 as it fulfils Condition A but is then set back to 1 as it fulfils Condition B

I would like to know if there is a way to exit the statement as soon as the condition is set to 0, without it moving through the whole IF statement ?

Thanks

05/22/2025 at 12:38 PM #247488 quote

JS
Participant

Master

An “early” exit is not possible… One possible solution is to adjust your conditions, for example:

If Condition A and Condition B then

X = 0

ElsIf Condition B then

X = 1

…

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05/22/2025 at 3:46 PM #247509 quote
robertogozzi
Moderator

Legend
ELSIF and ELSE are only executed alternatively:
```
IF ConditionA then
   X = 0                //the IF..ENDIF block is exited here
ELSIF ConditionB then
   X = 1                //the IF..ENDIF block is exited here
ELSIF ConditionC then
   X = 0                //the IF..ENDIF block is exited here
ELSE
   X = 1                //the IF..ENDIF block is exited here
ENDIF
```
I can’t see any condition overlapping any of the other ones.
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x-4.jpg
05/22/2025 at 3:50 PM #247512 quote
Iván González
Moderator

Legend
Hi! In ProBuilder, the structure IF ... ELSIF ... ELSE ... ENDIF is specifically designed to stop evaluating as soon as one condition is met. That means, if Condition A is true, the subsequent conditions (Condition B, C, etc.) are not evaluated at all. So, the behavior you’re describing, where X gets reassigned after meeting Condition A,should not happen if you’re using a proper ELSIF chain. Here you have an example:
```
ema=average[50](close)
if close > ema then
count1=1+count1
elsif close crosses over ema then
count2=1+count2
endif

return count1, count2 
```
Count2 will always be 0. If you use to if endif then it will be different:
```
ema=average[50](close)
if close > ema then
count1=1+count1
endif
if close crosses over ema then
count2=1+count2
endif

return count1, count2 
```
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