MT4 iFractals replacement

• 07/10/2017 at 9:10 AM #40201
  AVT

  I try to transscript a code from MT4 which is using the iFractals indicator. It’s an MT4 inline indicator and I cannot find any information what this indicator is calculating (just the usage syntax). Any ideas how to get around this?

  Thanks very much.

  

  AVT

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  07/10/2017 at 9:26 AM #40203
  GraHal

  Put the code on here and some kind soul may be able to help?

  Without the code it’s a guessing game?

  

  GraHal

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  07/10/2017 at 9:27 AM #40204
  Nicolas

  This is the code you need, I made long time ago for someone in the French forum:

  cp = 2 if high[cp] >= highest[2*cp+1](high) then LH = 1 else LH=0 endif if low[cp] <= lowest[2*cp+1](low) then LL= -1 else LL=0 endif if LH=1 then hil = high[cp] DRAWTEXT("▼",barindex[cp],hil,Dialog,Bold,12) coloured(100,100,100,100) endif if LL = -1 then LOL=low[cp] DRAWTEXT("▲",barindex[cp],lol,Dialog,Bold,12) coloured(100,100,100,100) endif return

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  cp = 2   if high[cp] >= highest[2*cp+1](high) then LH = 1 else LH=0 endif   if low[cp] <= lowest[2*cp+1](low)  then LL= -1 else LL=0 endif   if LH=1 then hil = high[cp] DRAWTEXT("▼",barindex[cp],hil,Dialog,Bold,12) coloured(100,100,100,100) endif   if LL  = -1 then LOL=low[cp] DRAWTEXT("▲",barindex[cp],lol,Dialog,Bold,12) coloured(100,100,100,100) endif   return

   

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  AVT

  

  Nicolas

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  07/10/2017 at 10:01 AM #40220
  AVT

  Thanks for your replies.

  @GraHal: Code is relatively simple (compare iFractals value to bars value), so I should get this going on my own. If I don’t try to do it on my own first instead of just asking “please can you code it for me”, I will never learn how to do it.

  
  @Nicolas: going to implement it and see what happens 🙂

  

  AVT

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  07/10/2017 at 1:02 PM #40239
  GraHal

  Ah sorry AVT, you said in your op … I try to transscript a code from MT4 … so I was suggesting you add the MT4 code on here.

  Let us know how you get on?

  

  GraHal

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  07/10/2017 at 8:11 PM #40293
  AVT

  Fractals part does now exactely what it should do, I limit the painting time. DF (words which you really should not say in public if you are civilized) – took me a whole day to understand it, but I think I got it now.

  
  @Nicolas  Just to see that I really got it:

  code snip

  cp = 2 if high[cp] >= highest[2*cp+1](high) then //if high[cp] >= highest[cp*cp+1](high) then

  1 2 3

  cp = 2 if high[cp] >= highest[2*cp+1](high) then //if high[cp] >= highest[cp*cp+1](high) then

  cp=2 must be a fixed value, because a valid fractal must be less than 4 – we count integers, so we count 3 (less than 4) -> makes us calculate with 3 candles back which is high[2] .

  The fractal formula which you use only works because 2*2 is the same as square of 2. If we would break the “valid” rule for a fractal and take iterations beyond 4, we must use the outcommented using the square. Correct?

  

  AVT

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