Help with money management

• 09/01/2019 at 1:00 PM #106071
  Fran55

  Please… I need this part of Code.

  If capital is Cross Up 10000€ the Next operations as to 3€.

  But, if capital is Cross down 10000€ the Next operations as to 1€.

  Thanks!

  

  Fran55

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  09/01/2019 at 2:17 PM #106079
  Vonasi

  capital = 10000 equity = capital + strategyprofit if equity > capital then positionsize = 3 else if equity <= capital then positionsize = 1 endif endif if (your conditions) then buy positionsize contracts at market endif

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  capital = 10000 equity = capital + strategyprofit   if equity > capital then positionsize = 3 else if equity <= capital then positionsize = 1 endif endif   if (your conditions) then buy positionsize contracts at market endif

  The above simply changes between position size of 3 or 1 depending upon if you are above or below 10k. Is this what you mean as your description is not very clear?

  

  Vonasi

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  09/01/2019 at 2:21 PM #106080
  Vonasi

  Another possibility:

  capital = 10000 equity = capital + strategyprofit once lastchange = capital once positionsize = 1 if equity > lastchange + 10000 then positionsize = positionsize * 3 lastchange = lastchange + 10000 else if equity < lastchange - 10000 then positionsize = max(1,positionsize / 3) lastchange = lastchange - 10000 endif endif if (your conditions) then buy positionsize contracts at market endif

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  capital = 10000 equity = capital + strategyprofit once lastchange = capital once positionsize = 1   if equity > lastchange + 10000 then positionsize = positionsize * 3 lastchange = lastchange + 10000 else if equity < lastchange - 10000 then positionsize = max(1,positionsize / 3) lastchange = lastchange - 10000 endif endif   if (your conditions) then buy positionsize contracts at market endif

  This version multiplies position size by 3 every time a new 10k profit is reached and divides it by 3 every time 10k is lost down to a minimum size of 1.

  Not tested.

  EDIT:2019/09/04. MIN in line 11 should have been MAX – I have edited the post to correct this.

  

  Vonasi

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  09/02/2019 at 12:55 PM #106228
  Fran55

  Thanks Vonasi!

  The first publicatión is valid.

  

  Fran55

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