Cruce de medias en diferentes velas

• 03/31/2022 at 5:45 PM #190877
  Fr7

  Hola, quería hacer el screener e indicador siguiente:

  1)En las 22 últimas velas la media 50 cruza por encima la media 200

  2)En la vela actual la media wilder 5 cruza por encima la media weighted 30

  A ver si alguien me puede decir si el código está correcto y por qué no obtengo resultados….

  Doble cruce

  result = 0 FOR i = 1 TO 22 DO if ExponentialAverage[50](close) crosses over Average[200](close) then result = 1 break endif NEXT c1=wilderAverage[5](close) crosses over WeightedAverage[30](close) SCREENER[c1 and result=1]

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  result = 0 FOR i = 1 TO 22 DO if ExponentialAverage[50](close) crosses over Average[200](close) then result = 1 break endif NEXT c1=wilderAverage[5](close) crosses over WeightedAverage[30](close) SCREENER[c1 and result=1]

   

  

  Fr7

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  03/31/2022 at 5:47 PM #190878
  Fr7

  Y aquí tampoco me dibuja ninguna flecha:

  result = 0 FOR i = 1 TO 22 DO if ExponentialAverage[50](close) crosses over Average[200](close) then result = 1 break endif NEXT c1=wilderAverage[5](close) crosses over WeightedAverage[30](close) if result = 1 AND c1 then drawarrowup(barindex,lowest[10](low)) coloured(0,51,255) endif RETURN

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  result = 0 FOR i = 1 TO 22 DO if ExponentialAverage[50](close) crosses over Average[200](close) then result = 1 break endif NEXT c1=wilderAverage[5](close) crosses over WeightedAverage[30](close) if result = 1 AND c1 then drawarrowup(barindex,lowest[10](low)) coloured(0,51,255) endif RETURN

   

  

  Fr7

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  03/31/2022 at 6:05 PM #190880
  robertogozzi

  La línea 3 debe decir:

  if ExponentialAverage[50](close)[i] crosses over Average[200](close)[i] then

  1	if ExponentialAverage[50](close)[i] crosses over Average[200](close)[i] then

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  Fr7

  

  robertogozzi

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