Bullish Bar Closing above 2 Bearish Bar and vice versa

parthapersonal · Tue, 14 Jul 2020 11:24:01 +0000

Hello, This simple code (if it can be simplified) can be used for identifying earliest reversals. The approach is to identify Bullish Bar Closing above 2 Bearish Bar and vice versa as shown in the document. The issue is if we use “if” statement then the program is becoming very big. Any simplification will be highly appreciated. Regards. c=close o=open l=low hi=high c1=c[1] c2=c[2] c3=c[3] c4=c[4] c5=c[5] c6=c[6] c7=c[7] c8=c[8] C9=C[9] c10=c[10] C12=C[12] o1=o[1] o2=o[2] o3=o[3] o4=o[4] o5=o[5] o6=o[6] o7=o[7] o8=o[8] O9=O[9] o10=o[10] O12=O[12] l1=l[1] l2=l[2] l3=l[3] l4=l[4] l5=l[5] l6=l[6] l7=l[7] l8=l[8] L9=L[9] h1=hi[1] h2=hi[2] h3=hi[3] h4=hi[4] h5=hi[5] h6=hi[6] h7=hi[7] h8=hi[8] H9=HI[9] h10=hi[10] H12=HI[12] if c>=o and c1<o1 and c2<o2 AND H1<H2 and c>h2 then t=10 ELSif c>=o and c1<o1 and c2>=o2 AND C3<O3 AND H1<H3 and c>h3 then t=10 elsif c>=o and c1<o1 and c2<o2 and c3<o3 and h1<h3 and h2<h3 and c>h3 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3<o3 and h2<h3 and c1<h3 and c>h3 then t=10 elsif c>=o and c1<o1 and c2<o2 and c3<o3 and h1>h2 and h2<h3 and c>h3 then t=10 ELSif c>=o and c1>=o1 and c2<o2 AND C3<O3 and c4<o4 AND H3<H4 and h2<=h4 and c1<=h4 and c>h4 then t=10 ELSif c>=o and c1<o1 and c2>=o2 AND C3<O3 and c4<o4 AND H3<H4 and c2<=h4 and c>h4 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4<o4 and h3<h4 and c1<h4 and c>h4 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3>=o3 and c4<o4 and h2<h4 and c1<h4 and c>h4 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3<o3 and c4<o4 and h3<h4 and c1<h4 and c>h4 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3<o3 and c4<o4 and h2>h3 and l2<l3 and h3<h4 and c1<h4 and c>h4 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and h3<h5 and c1<h5 and c>h5 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4<o4 and c5<o5 and h4<h5 and c3<h5 and c2<h5 and c1<h5 and c>h5 then t=10 elsif c>=o and c1<o1 and c2>=o2 and c3>=o3 and c4<o4 and c5<o5 and h4<h5 and c3<h5 and c2<h5 and c>h5 then t=10 elsif h4<h5 and c5<o5 and c4<o4 AND c3<=h5 and c2<=h5 and c1<=h5 and c>h5 AND C>=O then t=10 elsif c>=o and c1<o1 and c2<o2 and c3>=o3 and c4>=o4 and c5<o5 and c6<o6 and H5<h6 and c3<h6 AND C4<H6 and c>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4<o4 and c5>=o5 and c6>=o6 AND C7<O7 and H4<h7 and c3<=h7 AND C2<=H7 and c1<=H7 AND C>h7 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3>=o3 and c4>=o4 and c5<o5 and c6<o6 and H5<h6 and h2<h6 and c4<=h6 and c3<=h6 AND c1<=H6 AND C>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and c6<o6 and H5<=h6 and h3>=h6 and c4<=h6 and c2<=h6 AND c1<=H6 AND C>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4>=o4 and c5<o5 and c6<o6 AND C7<O7 and H6<h7 and h5>=h6 and c4<=h7 and c3<=h7 AND C2<=H7 and c1<=H7 AND C>h7 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4<o4 and c5>=o5 and c6<o6 AND C7<O7 and H6<h7 and c5<=h7 AND C3<=H7 AND C2<=H7 and c1<=H7 AND C>h7 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4<o4 and c5>=o5 and c6<o6 and h3=h4 and h4<h6 and c1<h6 and c>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4>=o4 and c5<o5 and c6<o6 and h5<h6 and c2<h6 and c1<h6 and c>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4<O4 and c5<o5 and c6<o6 AND H4>H5 and h5<h6 and c2<h6 and c1<h6 and c>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4>=O4 and c5<o5 and c6<o6 AND h5<h6 AND C4<=H6 AND C3<=H6 and c2<=h6 and c1<=h6 and c>h6 then t=10 elsif c>=o and c1<o1 and c2>=o2 and c3>=o3 and c4<O4 and c5>=o5 and c6<o6 AND h4<h6 AND C3<=H6 AND C2<=H6 and c>h6 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4>=O4 and c5>=o5 and c6<o6 AND h3<h6 AND C2<=H6 AND C1<=H6 ANd c>h6 then t=10 elsif h5<h6 and c6<o6 and c5<o5 AND c4<=h6 and c3<=h6 and c2<=h6 and c1<=h6 and c>h6 AND C>=O then t=10 elsif c>=o and c1<o1 and c2>=o2 and c3>=o3 and c4>=o4 and c5>=o5 and c6<o6 and c7<o7 and h6<h7 and c2<=h7 and c3<=h7 and c4<=h7 and c5<=h7 and c>h7 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and c6>=o6 and c7<o7 and h5<h7 and h3<h7 and c2<=h7 and c4<=h7 and c6<h7 and c1<=h7 and c>h7 then t=10 elsif c>=o and c1<o1 and c2>=o2 and c3>=o3 and c4<o4 and c5<o5 and c6>=o6 and c7<o7 and h5<h7 and h4>=h5 and H1>=H5 AND c2<=h7 and c3<=h7 AND c>h7 then t=10 elsif h5<h7 and c7<o7 and c5<o5 AND C6>O6 and c4<=h7 and c3<=h7 and c2<=h7 and c1<=h7 and c>h7 AND C>=O then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3>=o3 and c4>=o4 and c5<o5 and c6>=o6 and c7>=o7 and c8<o8 and h5<h8 and c1<h8 and c2<h8 and c3<h8 and c4<h8 and c>h8 then t=10 elsif c>=o and c1>=o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and c6>=o6 and c7>=o7 and c8<o8 and h5<h8 and c1<h8 and c2<h8 and c4<h8 and c>h8 then t=10 elsif c>=o and c1>=o1 AND c5<o5 and c6>=o6 and c7>=o7 and c8<o8 and h5<h8 and c1<h8 and c>h8 then t=10 elsif c>=o and c1>=o1 AND c2<o2 and c3>=o3 and c4>=o4 and c5<o5 and h2<h5 and c1<h5 and c>h5 then t=10 elsif c>=o and c1>=o1 AND c2>=o2 and c3<o3 and c4>=o4 and c5<o5 AND C6<O6 and h5<h6 AND C4<=H6 AND C2<=H6 and c1<=h6 and c>h6 then t=10 elsif c>=o AND C1<O1 and c2>=o2 and c3>=o3 and c4<o4 and c5>=o5 and c6>=o6 and c7>=o7 and c8<o8 and h4<h8 and c2<h8 and c>h8 then t=10 elsif c>=o AND C1>=O1 and c2>=o2 and c3<o3 and c4>=o4 and c5>=o5 and c6<o6 and c7<o7 and h6<h7 and c5<=h7 AND C4<=H7 and c2<=h7 AND C1<=H7 and c>h7 then t=10 elsif c>=o AND C1>=O1 and c2>=o2 and c3<o3 and c4>=o4 and c5>=o5 and c6>=o6 and c7<o7 and h3<h7 and c2<=h7 AND C1<=H7 and c>h7 then t=10 elsif c>=o and c1>=o1 and c2<o2 and c3<o3 and c4>=o4 and c5>=o5 and c6>=o6 and c7>=o7 and c8<o8 AND C9<O9 and h8<H9 AND H2>H3 and c1<h9 AND C>H9 then t=10 elsif h3<h5 and c5<o5 and c3<o3 AND c2<=h5 and c1<=h5 and c>h5 AND C>=O then t=10 elsif h6<h7 and c7<o7 and c6<o6 AND C5<=H7 and c4<=h7 and c3<=h7 and c2<=h7 and c1<=h7 and c>h7 AND C>=O then t=10 elsif h5<h8 and c8<o8 and c5<o5 AND c4<=h8 and c3<=h8 and c2<=h8 and c1<=h8 and c>h8 AND C>=O then t=10 elsif h6<h8 and c8<o8 and c6<o6 AND C5<=H8 and c4<=h8 and c3<=h8 and c2<=h8 and c1<=h8 and c>h8 AND C>=O then t=10 elsif h7<h8 and c7<o7 and c8<o8 and h6<h8 and c5<=h8 and c4<=h8 and c3<=h8 and c2<=h8 and c1<=h8 and c>h8 then t=10 elsif h7<h10 and c10<o10 and c7<o7 and c6<=h10 and c5<=h10 and c4<=h10 and c2<=h10 AND C1<=H10 and c>h10 then t=10 elsif h8<h9 and c9<o9 and c8<o8 and c7<=h9 and c6<=h9 and c5<=h9 and c4<=h9 and c3<=h9 and c2<=h9 and c1<=h9 and c>h9 then t=10 elsif h9<h10 and c10<o10 and c9<o9 and c8<=h10 and c6<=h10 and c5<=h10 and c4<=h10 and c2<=h10 and c>h10 then t=10 elsif h10<h12 and c10<o10 and c12<o12 and C9<=H12 AND c8<=h12 and C7<=H12 AND c6<=h12 and c5<=h12 and c4<=h12 AND c3<=h12 and c2<=h12 and c1<=h12 and c>h12 then t=10 elsif c<o and c1>=o1 and c2>=o2 and l1>l2 and c<l2 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3>=o3 AND L1>L3 AND c<l3 then t=-10 elsif c<o and c1<o1 and c2>=o2 and c3>=o3 and c1>l3 and c<l3 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3>=o3 and c4>=o4 and l3>l4 and c2>l4 and c<l1 and c<l4 then t=-10 elsif c<o and c1<o1 and c2<o2 and c3>=o3 and c4>=o4 and c5>=o5 and c1>l4 and c<l5 then t=-10 elsif l4>l5 and c5>=o5 and c4>=o4 and c3>=l5 and c2>=l5 and c1>=l5 and c<l5 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3>=o3 and l1 and c1>l4 and c<l5 then t=-10 elsif c<o and c1<o1 and c2>=o2 and c3<o3 and c4>=o4 and l2>l4 and c1>l4 and c<l4 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3<o3 and c4>=o4 and l1>l4 and c<l4 then t=-10 elsif c<o and c1<o1 and c2<o2 and c3>=o3 and c4>=o4 and l3>l4 and c1>l4 and c<l4 then t=-10 elsif c<o and c1<o1 and c2>=o2 and c3<o3 and c4<o4 and c5>=o5 and c6>=o6 and l5>l6 and c3>l6 and c1>l6 and c<l6 then t=-10 elsif c<o and c1<o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and c6>=o6 and l4>l6 and c3>l6 and c1>l6 and c<l6 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3>=o3 and c4<o4 and c5<o5 and l3>l6 and c2>l6 and c<l6 then t=-10 elsif c<o and c1>=o1 and c2<o2 and c3<o3 and c4>=O4 and c5>=o5 and l4>l5 and c2>=L5 AND C3<=L5 and c<l5 then t=-10 elsif c<o and c1<o1 and c2>=o2 and c3<o3 and c4>=o4 and c5<o5 and c6<o6 and c7>=o7 and l4>l7 and l2>l7 and c1>l7 and c<l7 then t=-10 elsif l6>l7 and c7>=o7 and c6>=o6 and c5>=l7 and c4>=l7 and c3>=l7 and c2>=l7 and c1>=l7 and c<l7 then t=-10 elsif l7>l8 and c8>=o8 and c7>=o7 and c6>=l8 and c5>=l8 and c4>=l8 and c3>=l8 and c2>=l8 and c1>=l8 and c<l8 then t=-10 elsif l8>l9 and c8>=o8 and c9>=o9 AND C7>=L9 and c6>=l9 and c5>=l9 and c4>=l9 and c3>=l9 and c2>=l9 and c1>=l9 and c<l9 then t=-10 elsif t[7]=10 and c7>=o7 and c5>=o5 and l5<=l7 and c2>=o2 and l2<=l5 and c<l2 and c<o then t=-10 endif return t as "2B-LS", 1 AS "L", -1 AS "S"

This topic has 22 replies, 3 voices, and was last updated 3 years ago by robertogozzi.

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07/21/2020 at 2:25 PM #139754

parthapersonal

Many thanks Robert. However it is still missing some signals as enclosed.

Regards,

parthapersonal

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07/21/2020 at 3:29 PM #139771

robertogozzi

The bar you marked as MISSESD, because you asked “bullish bar should close above the highest high of the previous 2 bearish bars (they (bullish and/ or bearish) may not be consecutive and the last bearish bar’s high should be lower than the previous bearish bar’s high ignoring the inside bar in between is any)“.

Which isn’t. The last bearish bar’s HIGH was HIGHER than the previous one!

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07/22/2020 at 8:40 AM #139800

parthapersonal

Hello Robert,

In that case the last bearish bar’s high when compared with the 3rd bearish bar (previous), it is low. Hence it should be considered for the signal. Similarly for the opposite.

Example for NEXTDC Ltd (ticker: NXT) the 17-Jul daily bar should be a signal as its close is higher than the high of the 3rd bearish bar as shown in the enclosed.

parthapersonal

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07/22/2020 at 11:40 AM #139821

robertogozzi

In that case the last bearish bar’s high when compared with the 3rd bearish bar (previous), it is low.

the last bearish bar’s high should be lower than the previous bearish bar’s high ignoring the inside bar in between is any

Which one of the two rules shall be applied?

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07/22/2020 at 1:05 PM #139846

parthapersonal

This is the paradox dear. Market does not always print as per our codes. My only intention is to capture the entire move, as much as possible and that is why I tried it with if statements which is capable of capturing all the variations. You are also right, however it would be better, for the time being, to follow in addition to existing codes, “the last bearish bar’s high when compared with the 3rd bearish bar (previous), it is low. Hence it should be considered for the signal. Similarly for the opposite.”

parthapersonal

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07/23/2020 at 12:36 AM #139934

robertogozzi

There you go (not tested):

DEFPARAM CalculateOnLastBars = 1000
Bullish   = close > open
Bearish   = close < open
InsideBAR = (range < range[1]) AND (high <= high[1]) AND (low >= low[1])
//
// DOWN trend detection
//
Count1 = 0
i      = 0
WHILE Count1 < 3 AND i < BarIndex
   i = i + 1
   IF Count1 = 0 THEN
      IF Bullish[i] AND Not InsideBAR[i] THEN
         Count1 = 1
         MyLO1 = low[i]
      ENDIF
   ELSIF Count = 1 THEN
      IF Bullish[i] AND Not InsideBAR[i] THEN
         Count1 = 2
      ENDIF
   ELSE
      IF Bullish[i] AND Not InsideBAR[i] THEN
         Count2 = 3
         MyLO2 = low[i]
         d1    = MyLO1 > MyLO2
         MyLO2 = min(MyLO1,MyLO2)
         Break
      ENDIF
   ENDIF
WEND
d2      = Bearish
d3      = close < MyLO2
Dcond   = d1 AND d2 AND d3
//
// UP   trend detection
//
Count2 = 0
j      = 0
WHILE Count2 < 3 AND j < BarIndex
   j = j + 1
   IF Count2 = 0 THEN
      IF Bearish[j] AND Not InsideBAR[j] THEN
         Count2 = 1
         MyHI1 = high[j]
      ENDIF
   ELSIF Count2 = 1 THEN
      IF Bearish[j] AND Not InsideBAR[j] THEN
         Count2 = 2
      ENDIF
   ELSE
      IF Bearish[j] AND Not InsideBAR[j] THEN
         Count2 = 3
         MyHI2 = high[j]
         u1    = MyHI1 < MyHI2
         MyHI2 = max(MyHI1,MyHI2)
         Break
      ENDIF
   ENDIF
WEND
u2      = Bullish
u3      = close > MyHI2
Ucond   = u1 AND u2 AND u3
//
Cond    = 0
IF Ucond THEN
   Cond = 1
ELSIF Dcond THEN
   Cond = -1
ENDIF
RETURN Cond AS "Signal"

DEFPARAM CalculateOnLastBars = 1000

Bullish = close > open

Bearish = close < open

InsideBAR = (range < range[1]) AND (high <= high[1]) AND (low >= low[1])

// DOWN trend detection

Count1 = 0

i = 0

WHILE Count1 < 3 AND i < BarIndex

i = i + 1

IF Count1 = 0 THEN

IF Bullish[i] AND Not InsideBAR[i] THEN

Count1 = 1

MyLO1 = low[i]

ENDIF

ELSIF Count = 1 THEN

IF Bullish[i] AND Not InsideBAR[i] THEN

Count1 = 2

ENDIF

ELSE

IF Bullish[i] AND Not InsideBAR[i] THEN

Count2 = 3

MyLO2 = low[i]

d1 = MyLO1 > MyLO2

MyLO2 = min(MyLO1,MyLO2)

Break

ENDIF

WEND

d2 = Bearish

d3 = close < MyLO2

Dcond = d1 AND d2 AND d3

// UP trend detection

Count2 = 0

j = 0

WHILE Count2 < 3 AND j < BarIndex

j = j + 1

IF Count2 = 0 THEN

IF Bearish[j] AND Not InsideBAR[j] THEN

Count2 = 1

MyHI1 = high[j]

ENDIF

ELSIF Count2 = 1 THEN

IF Bearish[j] AND Not InsideBAR[j] THEN

Count2 = 2

ENDIF

ELSE

IF Bearish[j] AND Not InsideBAR[j] THEN

Count2 = 3

MyHI2 = high[j]

u1 = MyHI1 < MyHI2

MyHI2 = max(MyHI1,MyHI2)

Break

ENDIF

WEND

u2 = Bullish

u3 = close > MyHI2

Ucond = u1 AND u2 AND u3

Cond = 0

IF Ucond THEN

Cond = 1

ELSIF Dcond THEN

Cond = -1

ENDIF

RETURN Cond AS "Signal"

robertogozzi

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07/23/2020 at 2:18 PM #139971

parthapersonal

Many thanks Robert, however it is missing many signals as enclosed.

parthapersonal

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Topics: 10

Replies: 71

Been thanked: 3 times

07/23/2020 at 2:51 PM #139976

robertogozzi

You asked me that you no longer check the last two bearish bars, but the last one and the second previous one (the last one and the thirs one).

When you want to check the last bars + the third one use the last version, if you want to use the last 2 bars (in both cases ignoring Inside bars) the use the previous version.

robertogozzi

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Topics: 69

Replies: 16475

Been thanked: 3643 times

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